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to (30 pts) A vertical angle of 18 20 30 is measured to the tip of...
Trigonometric Leveling ZA=93*10'27" HT-5.96 SD4721.68 5 2 1 instrument, a zenith angle of 9310'27" is measured...
Trigonometric Leveling ZA=93*10'27" HT-5.96 SD4721.68 5 2 1 instrument, a zenith angle of 9310'27" is measured to a target whose verti cal distance above Point X is 4.92 feet. The slope distance from the instrument to the target is 3162.48 feet. The elevation of Point X is 326.98 feet. With the instrument at the same location, a vertical angle (clevation angle) of 6'37'37" is measured to a target set at 5.96 feet vertically above Point 0. The slope distance from...
Q30: Trigonometric Leveling) Similar to Problem above, except the slope distance was 854.987 m, the zenith...
Q30: Trigonometric Leveling) Similar to Problem above, except the slope distance was 854.987 m, the zenith angle was 82° 13' 45"and the elevation of point P was 354.905 m above datum. What is the elevation of point Q? Q31: Trigonometric Levelingł In trigonometric leveling from point A to point B, the slope distance and zenith angle measured at A were 2504.897 m and 85° 08' 54". At B these measurements were 2504.891 m and 94° 52' 10"'respectively. If the instrument...
7. An elevation difference measurement by a total station is (a) is from the ground point...
7. An elevation difference measurement by a total station is (a) is from the ground point at the total station to the ground point at the prism computed from only slope distance and zenith angle (b) requires the horizontal circle to compute the elevation difference (c) requires sighting a known elevation on a backsight (d) usually requires height of instrument and height of target to be correctly derived 8. A horizontal angle at 2 from 1 to 3 is 65-08-10,...
Using a total station, a vertical angle of +5 28'12" was taken to a target set...
Using a total station, a vertical angle of +5 28'12" was taken to a target set 1.700 m above benchmark A of elevation 175.926 m. The EDM slope distance to a reflector set over benchmark A was 443.355 m. From the same setup, a vertical angle of +11°42'12" was then taken to a target set 1.300 m over a point B at the top of the hill and an EDM slope distance of 341.682 m was taken to a reflector...
1. A preengineering baseline was run down a very steep hill as shown in the diagram...
1. A preengineering baseline was run down a very steep hill as shown in the diagram below. Rather than measure horizontally downhill with the steel tape, the surveyor measured the vertical angle with a theodolite and the slope distance with an EDM. The vertical angle was -21°26', turned to a prism on a plumbed range pole 4.88 ft. above the ground. The slope distance from the theodolite to the prism was 148.61 ft. The theodolite's optical center was 4.66 ft....
3. (a) Assume that a light ray incident from air on a spherical raindrop of radius R at angle measured with respect...
3. (a) Assume that a light ray incident from air on a spherical raindrop of radius R at angle measured with respect to the surface normal undergoes one internal reflection before leaving the raindrop, as shown below. refraction Incident ray Internal reflection A refraction Use the area above to show that if ; = 0 and 2 = @it, then the total deflection angle 8 = 8 + 8 + 83 of the light ray is (in radians): 8 =...
Homework 8.1 Applications Score: 0/5 0/5 answered Question 1 Points A and B are separated by...
Homework 8.1 Applications Score: 0/5 0/5 answered Question 1 Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point Con land such than ZCAB = 43.8. Find the distance across the lake from A to B. B 5388 43.8° с 338 ft NOTE: The triangle is NOT drawn to scale. ft distance = Enter your answer as a number; your answer should be accurate to 2 decimal places. mework 8.1...
Problem 1 (15vpts) A proposed highway has two tangents of bearings N 75° 54' 36" E...
Problem 1 (15vpts) A proposed highway has two tangents of bearings N 75° 54' 36" E and N 53° 22' 30" W. The highway design engineer, attempting to obtain the best fit for the simple circular curve to join these tangents, decides that the external ordinate is to be 78.00 ft. The Pl is at station 65+43.21. Determine: (a) The external angle of the curve (A) (b) The radius of the curve (d) The station of the PC (f) The...
ses. Unless you need to edit, it's safer to stay in Protected View Enable Editing activate...
ses. Unless you need to edit, it's safer to stay in Protected View Enable Editing activate now. Reactivate 1. Given an angle of 18°15'02', convert the angle to degrees with decimal rounded to the nearest 0.001" (4 pts.) 2. Given an angle of 48.871", convert the angle to degrees, minutes, and seconds (DMS). Round to the nearest second. (4 pts.) 3. A downhill slope measures 402.22' from point to point D. Both points are on the ground. The elevation at...
2. A crate is pushed horizontally at an angle of 20° across a rough surface as...
2. A crate is pushed horizontally at an angle of 20° across a rough surface as shown. The mass of the crate is 55 kg and the coefficient of kinetic friction M = 0.35. a) What applied force is required to keep the box moving at a constant acceleration of 3m/s2 ? b) What applied force is needed to keep the box moving at a constant speed, that is, no acceleration? (2 pts.) 3. A 60-kg skier starts from rest...
Trigonometric Leveling ZA=93*10'27" HT-5.96 SD4721.68 5 2 1 instrument, a zenith angle of 9310'27" is measured to a target whose verti cal distance above Point X is 4.92 feet. The slope distance from the instrument to the target is 3162.48 feet. The elevation of Point X is 326.98 feet. With the instrument at the same location, a vertical angle (clevation angle) of 6'37'37" is measured to a target set at 5.96 feet vertically above Point 0. The slope distance from...
Q30: Trigonometric Leveling) Similar to Problem above, except the slope distance was 854.987 m, the zenith angle was 82° 13' 45"and the elevation of point P was 354.905 m above datum. What is the elevation of point Q? Q31: Trigonometric Levelingł In trigonometric leveling from point A to point B, the slope distance and zenith angle measured at A were 2504.897 m and 85° 08' 54". At B these measurements were 2504.891 m and 94° 52' 10"'respectively. If the instrument...
7. An elevation difference measurement by a total station is (a) is from the ground point at the total station to the ground point at the prism computed from only slope distance and zenith angle (b) requires the horizontal circle to compute the elevation difference (c) requires sighting a known elevation on a backsight (d) usually requires height of instrument and height of target to be correctly derived 8. A horizontal angle at 2 from 1 to 3 is 65-08-10,...
Using a total station, a vertical angle of +5 28'12" was taken to a target set 1.700 m above benchmark A of elevation 175.926 m. The EDM slope distance to a reflector set over benchmark A was 443.355 m. From the same setup, a vertical angle of +11°42'12" was then taken to a target set 1.300 m over a point B at the top of the hill and an EDM slope distance of 341.682 m was taken to a reflector...
1. A preengineering baseline was run down a very steep hill as shown in the diagram below. Rather than measure horizontally downhill with the steel tape, the surveyor measured the vertical angle with a theodolite and the slope distance with an EDM. The vertical angle was -21°26', turned to a prism on a plumbed range pole 4.88 ft. above the ground. The slope distance from the theodolite to the prism was 148.61 ft. The theodolite's optical center was 4.66 ft....
3. (a) Assume that a light ray incident from air on a spherical raindrop of radius R at angle measured with respect to the surface normal undergoes one internal reflection before leaving the raindrop, as shown below. refraction Incident ray Internal reflection A refraction Use the area above to show that if ; = 0 and 2 = @it, then the total deflection angle 8 = 8 + 8 + 83 of the light ray is (in radians): 8 =...
Homework 8.1 Applications Score: 0/5 0/5 answered Question 1 Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point Con land such than ZCAB = 43.8. Find the distance across the lake from A to B. B 5388 43.8° с 338 ft NOTE: The triangle is NOT drawn to scale. ft distance = Enter your answer as a number; your answer should be accurate to 2 decimal places. mework 8.1...
Problem 1 (15vpts) A proposed highway has two tangents of bearings N 75° 54' 36" E and N 53° 22' 30" W. The highway design engineer, attempting to obtain the best fit for the simple circular curve to join these tangents, decides that the external ordinate is to be 78.00 ft. The Pl is at station 65+43.21. Determine: (a) The external angle of the curve (A) (b) The radius of the curve (d) The station of the PC (f) The...
ses. Unless you need to edit, it's safer to stay in Protected View Enable Editing activate now. Reactivate 1. Given an angle of 18°15'02', convert the angle to degrees with decimal rounded to the nearest 0.001" (4 pts.) 2. Given an angle of 48.871", convert the angle to degrees, minutes, and seconds (DMS). Round to the nearest second. (4 pts.) 3. A downhill slope measures 402.22' from point to point D. Both points are on the ground. The elevation at...
2. A crate is pushed horizontally at an angle of 20° across a rough surface as shown. The mass of the crate is 55 kg and the coefficient of kinetic friction M = 0.35. a) What applied force is required to keep the box moving at a constant acceleration of 3m/s2 ? b) What applied force is needed to keep the box moving at a constant speed, that is, no acceleration? (2 pts.) 3. A 60-kg skier starts from rest...
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