I. For the circuit in Fig. 5, use steady-state analysis to 5003 250 23 125cos(12,5001) mA...
20Ω 30 Ω j20Ω Fig. 1.7 In the circuit of Fig. 1.8, find the RMS phasor voltage V so that the 60 Ω resistor absorbs an average power of 240 W. Hence, determine the complex power delivered to each component, the complex power and the power factor delivered by voltage source. Fig. 1.8 2) P1.8
7. The expressions for the steady-state voltage and current at the terminals of the circuit seen in Fig. P9.14 are Ug = 300 cos (5000 + 78*) V, 's = 6 sin (5000?1+ 123°) A a) What is the impedance seen by the source? b) By how many microseconds is the current out of phase with the voltage? Figure P9.14 2, Circuit
250 22 Problem 3. (9 Points) In the adjoining circuit schematic, in steady-state, the current flowing through the loop causes a voltage drop across the resistor, having the waveform vr(t) = 15 cos (75 t) and a voltage drop across the capacitor given by ve(t) = 20 cos (75 t +90) (a) Express the above two voltages in phasor form. (b) Find the source voltage shown in the circuit schematic, expressed in phasor form. (c) Express the source voltage v(t)...
Name 7. For the following circuit: a. b. c. d. Find the (steady-state) mesh currents as functions of time. Find the complex What is the PFA for the voltage source? As seen by the voltage source, is capacitive? power supplied by the voltage source. the circuit pri marily ind uctive or primarily 10 uF 0.25 H 50 0 50 cos(377t + 459) V sin(377t) A
esign the current divider circuit shown in Fig. 5 such that it produces the branch currents of 16.67 mA, 10 mA, and 6.67 mA, as indicated. Since a true current source is not available, it is implemented here as a 15-volt source in series with a 100 Ω resistor. It is therefore necessary to choose Rı, R2, and Rs so that the total supplied current is Is- 33.33 mA, and the three branch currents are as shown. Table I -...
2502 In the adjoining circuit schematic, in steady-state, the current flowing through the loop causes a voltage drop across the resistor, having the waveform vr(t) = 15 cos (75 t) and a voltage drop across the capacitor given by ve(t) = 20 cos (75 t +90°) (a) Express the above two voltages in phasor form. (b) Find the source voltage shown in the circuit schematic, expressed in phasor form. (c) Express the source voltage v(t) as a function of time....
2- (4 Points) For the following network, draw the steady state circuit, then calculate the energy stored in the capacitor and in the inductor and the power dissipated in each resistor. .- 2 mH m + MA 30 k12 20k2 6uF V
A buck converter is operating in the steady state with an input voltage of = 42 V dc, D = 0.3, output power of 24 W, an inductance of 25 H and a switching frequency of 400 kHz. Draw the input current, inductor current, inductor voltage, and capacitor current waveforms. Assume the dc component of the inductor current flows through to the load and the ac component of the inductor current flows through the capacitor. Assume ideal circuit components.
derive a differential equation for ??(?) (The current through the indcutor) for the circuit. Define state variables, to compute ??(?) and ??(?)(voltage across the inductor). t 0 C w 2 L 8 he circuit parameters in the circuit in Fig. P12.31 are R 1600 2; L 200 mH; and C 200 nF. If ,(t)-6 mA, find
IV The expressions for the steady-state voltage and current at the terminals of the circuit shown below are Vg-300 cos(5000t+78"N , i,-6 sin(5000t+ 1 23°) A Circuit (a) What is the impedance seen by the source? (b) By how many microseconds is the current out of phase with the voltage?