Question

3. A rotating merry-go-round makes one complete revolution in 4.0s (sce figure below). (a) What is the lincar speed of a child seated 1.2 m from the center? (b) What is her acceleration (give components). (c) Her dad gets overzealous and spins the merry-go-round faster and faster if the child has a weight of 40 lbs and a cocfficient of friction of 0.5 what is the fastest speod that she can be moving (in m/s) bef off the merry-go-round?

i need the answer for part c

Answer 1

When merry - go round rotates the child will experience an outward force known as centrifugal force (F_c) F_c = m v^2/R This centripetal force is balanced by fiction force (f) f = mu m g V is the fastest speed m V^2/R = mu m g [g = 9.8 m/s^2] V^2/1.2 = 0.5 times 9.8 V^2 = 5.88 Therefore V = 2.425 m/s