Question

An open traverse was run as shown below from A to D via B and C, because points A and D are not inter visible. The results of the traverse are as follows: POINT DISTANCE INTERIOR ANGLE A A B 478.20 1190 40' ig40 692.15 860 15' C 781.40 D C. D Calculate a) the angle, to the nearest 01', at A needed to define the direction of AD with respect to AB, and b) the length of AD to the nearest 0.01m Hint: Assume an arbitrary bearing for the line AB. 8 15 m

Answer 1

Let AB be North line bearing a o = 180 - 119° 40' = 60°20' 6.360 (180-0) -86 15 15H s' o id are bearings of Blico respectudy Let E IN of Ale Co,o the Bearing E IN 86 is 8c length point B 478.20 od 6+478.2 0 = 0, ot 478.260 = 478.2 692.15 60 20 10+ 692.15 66 o 20 1478.2+692.15 Cos 6026 b 781.40 154 5 - Gol.42; - 820.78 D = 601142 + 781.4 Silsis = 942.94 IDN = 820.78 + 78114 Cas 150 s'= 117.96 Longth A B = V(De-Me)² + (0-A) V (942.94-0² + (117:96-02 AD = 9.50.29m 2= L (or-Ac)/AD) - Lil (941294-0/950.29) = 82531