Question

TPE2601/101/0/2019 Answer all questions (134 Marks) ASSIGNMENT 2 QUESTION 1 Consider the following traverse from A to E, along the horizontal alignment of a rural highway near Fouriesburg in the Free State. The bearings and distances between successive points are shown on the drawing below, where the bearing (e) and distance (d) C to D are missing. Horizontal curves must be introduced at B, C and D 277029'13" C. B 1592.500 m NORTH e) (d 207009'47 00.100 m 289050'46" 1141.900 m NOT TO SCALE A Curve X Y Radius (m) Chainage Point 284 854.900 -267 577.800 0.000 A ? ? 450 B ? 550 C ? 350 D -271 375.106 284 845.796 E TPE2601/101/0/2019 Use the information provided on the drawing and the table above to answer the following questions: (12) 1.1 Perform polar calculations to derive the coordinates of point B, C, and D. (4) 1.2 Perform join calculations to derive the distance and bearing on line C to D. Calculate all the following elements of the horizontal curves occurring along the 1.3 centreline (3 1.3.1 Intersection angles: (AB, Ac and AD) (3) 1.3.2 Tangent lengths: (TB, Tc and TD) (3) 1.3.3 Curve lengths: (LB, Lc and LD) Calculate the chainages along the road centreline for all BCs, MPs and ECs as well as (10) 1.4 point E [35 marks] TPE2601/101/0/2019 Use the information provided on the drawing and the table above to answer the following questions: 1.1 Perform polar calculations to derive the coordinates of point B, C, and D. (12) 1.2 Perform join calculations to derive the distance and bearing on line C to D. (4) 1.3 Calculate all the following elements of the horizontal curves occurring along the centreline 1.3.1 Intersection angles: (AB, Ac and Ap) (3) 1.3.2 Tangent lengths: (Ts, Tc and To) (3) 1.3.3 Curve lengths: (LB, Lc and LD) (3) Calculate the chainages along the road centreline for all BCs, MPs and ECs as well as (10) 1.4 point E. 35 marks]

Answer 1

267 57 7 8 L DAG r070147 LAR Cas 207047 -621 887 3 19.61 ac 1512.5m 284 535.287 268 100.687 lee las 277'29'2 Lec Dec -BC -1578.913 207.503 2829S6 36H 28H 8 794 -2713 75 La6 vE 387 669 Dr Ex-DaE Ey-Loe Dya 185919.87 -271702-775 Oca- D C - 2963 SI2 Dy-Cy Lco -376 9 S9 apLeatD 17 95016 m tanLeeloeae -SIGIC Rearing cn- 360-5 826 1 1 7 o 26 13 277 29 t 10 23 302 1 11 18 19 37 1815046 AP 3 08 1023 1

5Sam 350ma lenpthe Tea Rata Anla Re ta Ac/2 /7 Rota Aol 56 159m urwe JRe Aalieo 5 S 3 3 Les 29H 56 ILL95 3 Chaicayes A 383.10 7 7o0 1- 316993 Cunue R ip Cunue R 383.107 t(5s2 313 659285 93 5H3 Cunne B 383 i7 5s313 4 316.993-LSoo7 unne C 935H3 + La - 29H.SC6/2 1207.313 -235H SA 2660 0 3t 294.560 Cuere D 35H S t47902-1S90 7- -Curu LLL953/-1qe 2311 C

Length of line AB is assumed as 700.100m, since it is not clear

Direction of North is in contradiction with the bearings given, it seems more like direction of South.

If clarifications needed anywhere, kindly refer back.