Solution :
Given that ,
mean = = 63.4
standard deviation = = 2.7
(a)
P(x < 64) = P[(x - ) / < (64 - 63.4) / 2.7]
= P(z < 0.22)
= 0.5871
The probability is approximately 0.5871
(b)
= / n = 2.7 / 49 = 0.3857
P( < 64) = P(( - ) / < (64 - 63.4) / 0.3857)
= P(z < 1.56)
= 0.9406
The probability is approximately 0.9406
Assume that women's heights are normally distributed with a mean given by = 63.4 in, and...
Assume that women's heights are normally distributed with a mean given by μ-63.4 in, and a standard deviation given by σ= 1.8 in (a) If 1 woman is randomly selected, find the probability that her height is less than 64 in (b) If 33 women are randomly selected, find the probability that they have a mean height less than 64 in. (a) (Round to four decimal places as needed.) (a) The probability is approximately (b) The probability is approximately (Round...
Assume that women's heights are normally distributed with a mean given by p=63 3 in, and a standard deviation given by o =26 in. (a) If 1 woman is randomly selected, find the probability that her height is less than 64 in (b) 49 women are randomly selected, find the probability that they have a mean height less than 64 in (a) The probability is approximately (Round to four decimal places as needed) (b) The probability is approximately (Round to...
Assume that women's heights are normally distributed with a mean given by h = 63.7 in, and a standard deviation given by o = 3.1 in. Complete parts a and b. a. If 1 woman is randomly selected, find the probability that her height is between 63.6 in and 64.6 in. The probability is approximately (Round to four decimal places as needed.) b. If 20 women are randomly selected, find the probability that they have a mean height between 63.6...
Assume that women's heights are normally distributed with a mean given by u = 63.7 in, and a standard deviation given by o = 3.1 in. Complete parts a and b. a. If 1 woman is randomly selected, find the probability that her height is between 63.6 in and 64.6 in. The probability is approximately (Round to four decimal places as needed.) b. If 20 women are randomly selected, find the probability that they have a mean height between 63.6...
Assume that women's heights are normally distributed with a mean given by mu equals 63.5 in, and a standard deviation given by sigma equals 2.6 in. (a) If 1 woman is randomly selected, find the probability that her height is less than 64 in. (b) If 44 women are randomly selected, find the probability that they have a mean height less than 64 in.
Assume that women's heights are normally distributed with a mean given by μ=64.9 in, and a standard deviation given by σ=2.3 in. Complete parts a and b. a. If 1 woman is randomly selected, find the probability that her height is between 64.6 in and 65.6 in. The probability is approximately _____. (Round to four decimal places as needed.)
Assume that women’s heights are normally distributed with a mean given by µ = 63.5 in, and a standard deviation given by σ = 2.9 in. If 1 woman is randomly selected, find the probability that her height is less than 61 in. Round to four decimal places and leave as a decimal If 70 women are randomly selected, find the probability that they have a mean height less than 64 in. Round to four decimal places and leave as...
Assume that women's heights are normally distributed with a mean given by μ=62.2 in,and a standard deviation given by σ=2.8 in. (a) If 1 woman is randomly selected, find the probability that her height is less than 63 in. (b) If 35 women are randomly selected, find the probability that they have a mean height less than 63 in.
Assume that women's heights are normally distributed with a mean given by mu equals 64.8 inμ=64.8 in , and a standard deviation given by sigma equals 3.2 inσ=3.2 in. Complete parts a and b. a. If 1 woman is randomly selected, find the probability that her height is between 64.364.3 in and 65.365.3 in.The probability is approximately nothing. (Round to four decimal places as needed.)
Question Help Assume that women's heights are normally distributed with a mean given by mu equals μ=62.4 in, and a standard deviation given by sigma equals σ=2.9 in. (a) If 1 woman is randomly selected, find the probability that her height is less than 63 in. (b) If 44 women are randomly selected, find the probability that they have a mean height less than 63 in.