Question

A-Select the correct expressions for vo(t) that apply in the interval t<0.

B- Select the correct expressions for vo(t) that apply in the interval 0≤t≤4ms.

C-Select the correct expressions for vo(t) that apply in the interval 4ms≤t≤8ms.

D-Select the correct expressions for vo(t) that apply in the interval 8ms≤t≤∞

E- Select the correct expressions for vo(t) that apply in the interval t<0 with RR reduced to 50kΩ

F- Select the correct expressions for vo(t) that apply in the interval 0≤t≤4ms with RR reduced to 50kΩ

G- Select the correct expressions for vo(t) that apply in the interval 4ms≤t≤8ms with RR reduced to 50kΩ

H- Select the correct expressions for vo(t) that apply in the interval 8ms≤t≤∞ with RR reduced to 50kΩ

0,(V) 100 1 (ms) -100

Answer 1

Given AV (v) circuit R = 200K2 mo 100 8 t (ms) 4 25 of TV 25 F A) For to there so wulpto to is no input. volt) = OV B: For ostbums octcums Volt)= VP+ [vot - Vode tlp T = RXc = 200x103 x 25 xiola ༤ 5 ms Yo = 200 5' Iva = 100 Vot zo Volt) = 100+ (0-100] © 2007 I vore) = 100-1002 200ty o Ltrums Vo (4m) = 100-100ě 4x10°*200 v = 100-44.93 = 55.067 V

For 4ms attoms Vm= -1000 VH+ = 55.067 v No (t) = -100+ [55.067 - 610078 200(t-4m) 4mscts sms l volo) = -100 + 155.0678200 (t -0.004) v Volems) = -100+ 155.067-200 (0.008-0-004) -0.8 -100 +155067 = -30.32 V 0 $mse tsoo Voo=0 Vgt = -30.32 v Vo(t) = 0+T-30-32-676-200 (+-0.008) volt) -30.32 € 200 (+-0.008) vlmse

E) Modified circuit 50K ug & T 25 nF Volt) For tho, no input voltage - 30 volt) =ov F octeums T= RXC = 50x103 x 25 x15 12 = 1250 x109 Te 1-25 ms Yo = 500 Voo = 100 v vot = or Touteums Volt) = 100+ (0-100] e sootu = 100-1002800t v - 800 x 4x103 volums) = 100-1000 = 100 -1002362 = 45.92 v

ums t tasms Vo = -100v Vit = 95.92 V Volt) = 1-800(t-0.004) -100+505.92-6-100)]e Vott) = -100 + 195.92 ē soolt-0.004) v lumsatz vo (8ms) = -100+ 195.92 é 800 (8X10° -0.004) -3-2 -100+ 195.92e = = -92-01 V 8ms L teo vozov Vet - -9201V volt) = 0 +(-42.01-0] =800(-0.008), 1 volt) = -92.01€ 800 (t-0-00%) y &msetkop