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3. A piece of wire 2 cm long is inside a solenoid with 2000 turns/m. The table shows a measurement of the force exerted on th

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Answer #1

The magnetic force on the small piece of wire is:

F = BILsin90 = BIL

where B = magnetic field due to the solenoid which is: B=\mu_o (N/l)I

so, F=\mu_o nI^2L

where n = 2000 turns/m and L = 2cm = 0.02 m

=> F = 40μο!

this is of the form: y = ax2

so, the graph of Force vs current will be an upward parabola.

The data given above does not support this force-current trend as it does not give an accurate value of permeability of free-space which is 4π × 10-7-1.2566 × 10-bT7n/A Ho .

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