(1 point) Find yy as a function of xx ify′′′+64y′=0,y‴+64y′=0,y(0)=−1, y′(0)=−16, y′′(0)=−192.y(0)=−1, y′(0)=−16, y″(0)=−192.y(x)=
(1 point) Find yy as a function of tt if4y′′+28y′+49y=0,4y″+28y′+49y=0,y(0)=6,y′(0)=7.y(0)=6,y′(0)=7.y=y=
(1 point) Find y as a function of t if y" – 107 +9y = 0, y(0) = 4, y(1) = 3. y(t) = Remark: The initial conditions involve values at two points.
Problem 3. (1 point) Find y as a function of tif y" - 7 - 8y = 0, y(O) = 8, y(1) = 4. y) = Remark: The initial conditions involve values at two points.
(1 point) Find y as a function of t if 121y" + 22y' + y = 0, y'(0) = 7. y(0) = 9, y =
(1 point) Find y as a function of t if y-8y = 0, (0) - 6, (1) = 2. y(t) Remark The initial conditions involve values at two points
(1 point) Find y as a function of t if 2y" + 33y = 0, y(0) = 3, y' (0) = 9. g(t) = Note: This particular webWork problem can't handle complex numbers, so write your answer in terms of sines and cosines, rather than using e to a complex power.
(1 point) Find y as a function of lif y" - 11y +24y = 0 y(0) - S WI) = 4 W = Remark: The initial conditions involve values at two points. Problem 4. (1 point) Find the solution to the linear system of differential equations 59x +84 -42x - 607 satisfying the initial conditions (0) = 10 and y(0) -7. = X(t) = y = Note: You can earn partial credit on this problem.
(1 point) Find y as a function of t if y" – 11y' + 24y = 0, y(0) = 6, y(1) = 5. y(t) Remark: The initial conditions involve values at two points.
Consider the intial value problem: 81y" + 72y' + 16y= 0, y(0) = a > 0, y'(0) = -1. a. Find the solution in terms of a. Give your answer as y=... . Use x as the independent variable. Answer: b. Find the critical value of a that separate solutions that become negative from those that are always positive. critical value of a =