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a photon is emitted when an electron in the He+ atom jumps from the n=4 state...

a photon is emitted when an electron in the He+ atom jumps from the n=4 state to the n=1 state. calculate the energy, wavelength, and frequency of the photon

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Answer #1

The energy of emitted photon is 13.6 eV13.6 eV -40.8 eV The wavelength of the photon is 1240 eV nm. 304 nm he AE λ=-= nm -= 4

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