Question

7. You are asked to design a horizontal curve with a 40-degree central angle for a two-lane road with 10-ft lanes. The design speed is 70mph, superelevation is 6%, and the coefficient of friction is 0.10. Determine the radius, degree of curvature, and the curve length. [8 points] 8. For the horizontal curve in the above problem, what distance must be cleared from the inside edge of the inside lane to provide adequate stopping distance? [6 points]

NUMBER 8 ONLY

Answer 1

7. design speede 70 mph a. 70 x 1.60934 soxan kaph. 112.6532 kmph 31.2929 misce.. exte 12ER. (31.2927) 127 lett) 127 (0.ob+ 0.1) Radius : 48.19 mts. Degree of currichre a 1420 De 35.699 44.19 X 40 T80 curve length a bez Ro 33.64 mits. : Set Back distance : 29 . SSD Lc .. Stopping sista distance SSD e Vetemente . (34.2927) (31.2927) (2-5) + 2x9.91801 547.331 mts. le < SSD x2 40° given. set back distance - R-(R-d) Call +(5-4) sino . from centre line y roed dy arstance betweeni S ceritre line į road and a cenite line of inner lone edz stt : 1.524 mts. setback- distance from cenine line y road 2 49.19 - (48:19 -1.524) cws 20' 1577.331- 83.64 simo * 4.3383 + 92.9766 97.315 mts. 2 5-M

I. In question it is used to calculate from , inside edge of Innen lane Obtained value lone - - lane-2 Sz 99,315 mts s'z s- 10 feet as- 3.048mts (97.315 -3.048 sa 94.267 mts mts

I have used S.I. units to solve this problems. Appropriate conversions can be done.

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