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Problem #5 Given the following data for a vertical curve of a road: G1 = -2.5%,...
(A) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00...
(A) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00 ft, BVC Station = 10+00.00, BVC Elev = 5000.00 ft. EVC Station = ? (b) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00 ft, BVC Station = 10+00.00, BVC Elev = 5000.00 ft. EVC Elevation = ? (D) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00 ft, BVC Station =...
A 1080 ft long tangent crest vertical curve connects tangents ( G1= 4% , G2 =...
A 1080 ft long tangent crest vertical curve connects tangents ( G1= 4% , G2 = -2.8%). The two stations intersect at ghost station 640+00 where elevation is 1325.000 ft. Determine the stationing and elevations of the following points. 1. PVC 2. PVT 3. High point 4. 640+20
Problem 6 Use the following data to calculate the layout of an equal tangent vertical curve...
Problem 6 Use the following data to calculate the layout of an equal tangent vertical curve by offsets for every full station. Use Wolfpack for the calculations and provide an image of the output file. g1 = -1.20% g2 = +2.50% X PVI = 48+70 Y PVI = 5,893.48 L = 1500' Y = Yevc +81X+ ) x2 Problem 7 Using the data and results of vertical curve Problem 6, calculate the station and elevation of the high (or low)...
6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.-...
6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.- 1 134.50, gi-30%, g2+ +1.4%, L :300, what is the station and elevation of the BVC? a) 17+00; 1138.00 17+00; 1139.44 h9+50; 1142.00 d) 19+50; 1138.00 7. Based on the following Vertical Curve information (units in ft.): PVI Sta 1 134.50, gi .-30%, g2+ +1.4%, L . 500, what is the elevation on the curve at Sta. 23 22+00, PVI Elev. a) 1138.49 b)...
The data given for a vertical sag curve on a roadway plan and profile sheet are...
The data given for a vertical sag curve on a roadway plan and profile sheet are as follows: PVI station 32+11.61, PVI elevation 54.18 ft, back tangent gradient gi4.00 percent, forward tangent gradient g, 7.00 percent, and length of curve L- 600 ft. Determine the curve elevations at half-station intervals along the curve, and compute the sta elevation of the lowest point. tion and い600 ft PVT 35+11.61 Elev. 75.18 35 34 PVC 29 11.61 Elev 66.18 Low point 31...
You are designing a new road for a two-lane highway. In order to intersect with an...
You are designing a new road for a two-lane highway. In order to intersect with an existing road, the new road must meet the existing road at an elevation of 440.50 ft at station 192+ 56.00 Your new road has an initial tangent of +2.0% and a final tangent of-1.5%. The PVI is located at station 19150.00 and elevation 450.00 ft. Find the length of the curve necessary for this alignment. What is the maximum recommended design speed limit based...
Help please 2 (36 Pts) A 4250 ft equal tangent parabolic vertical curve has a back...
Help please
2 (36 Pts) A 4250 ft equal tangent parabolic vertical curve has a back tangent grade (gl) of + 3.6 % and a forward tangent grade (g2) of-1.8 %. If the elevation of the PVI is 4264.82 ft. at station 78+ 25.00; what is: (a) the elevation and stationing of the PVC and PVT; (b) the elevation of the curve at station 83 + 63.00; and (c) the elevation and stationing of the highest and lowest points on...
25. A spiral curve with a length of 50 feet connects a tangent to a curve...
25. A spiral curve with a length of 50 feet connects a tangent to a curve having a radius of 100 feet. Deter- mine the offset from the tangent to the point where the spiral connects to the curve and the length of throw from the tangent. 26. Given a spiral curve with a length of 150 feet, which connects a tangent to a curve having a radius of 200 feet, determine the offsets from the tangent to the midpoint...
2. Given a sag vertical curve connecting a -1.5% grade with a +2.5% grade on a...
2. Given a sag vertical curve connecting a -1.5% grade with a +2.5% grade on a rural arterial highway, use the rate of vertical curvature and a design speed of 70 mi/h to compute the elevation of the curve at 100 ft stations if the grades intersect at station (475+00) at an elevation of 300.00 ft. Identify the station and elevation of the low point.
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station...
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station Tangent Elevation Tangent Offset В VC 45+00 45+50 46+00 PVI 678.14 46+18.47 46+50 47+00 47+50 EVC I. gl=+4.3%, g2 =-3.196, L = 300, 2. Calculate stations for BVC and EVC and insert into table 3. Calculate station for high/low point and insert into table (this will be located between stations already entered in table, and not yet highlighted). 4. Calculate ALL tangent elevations, tangent...
Problem 6 Use the following data to calculate the layout of an equal tangent vertical curve by offsets for every full station. Use Wolfpack for the calculations and provide an image of the output file. g1 = -1.20% g2 = +2.50% X PVI = 48+70 Y PVI = 5,893.48 L = 1500' Y = Yevc +81X+ ) x2 Problem 7 Using the data and results of vertical curve Problem 6, calculate the station and elevation of the high (or low)...
6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.- 1 134.50, gi-30%, g2+ +1.4%, L :300, what is the station and elevation of the BVC? a) 17+00; 1138.00 17+00; 1139.44 h9+50; 1142.00 d) 19+50; 1138.00 7. Based on the following Vertical Curve information (units in ft.): PVI Sta 1 134.50, gi .-30%, g2+ +1.4%, L . 500, what is the elevation on the curve at Sta. 23 22+00, PVI Elev. a) 1138.49 b)...
The data given for a vertical sag curve on a roadway plan and profile sheet are as follows: PVI station 32+11.61, PVI elevation 54.18 ft, back tangent gradient gi4.00 percent, forward tangent gradient g, 7.00 percent, and length of curve L- 600 ft. Determine the curve elevations at half-station intervals along the curve, and compute the sta elevation of the lowest point. tion and い600 ft PVT 35+11.61 Elev. 75.18 35 34 PVC 29 11.61 Elev 66.18 Low point 31...
You are designing a new road for a two-lane highway. In order to intersect with an existing road, the new road must meet the existing road at an elevation of 440.50 ft at station 192+ 56.00 Your new road has an initial tangent of +2.0% and a final tangent of-1.5%. The PVI is located at station 19150.00 and elevation 450.00 ft. Find the length of the curve necessary for this alignment. What is the maximum recommended design speed limit based...
Help please
2 (36 Pts) A 4250 ft equal tangent parabolic vertical curve has a back tangent grade (gl) of + 3.6 % and a forward tangent grade (g2) of-1.8 %. If the elevation of the PVI is 4264.82 ft. at station 78+ 25.00; what is: (a) the elevation and stationing of the PVC and PVT; (b) the elevation of the curve at station 83 + 63.00; and (c) the elevation and stationing of the highest and lowest points on...
25. A spiral curve with a length of 50 feet connects a tangent to a curve having a radius of 100 feet. Deter- mine the offset from the tangent to the point where the spiral connects to the curve and the length of throw from the tangent. 26. Given a spiral curve with a length of 150 feet, which connects a tangent to a curve having a radius of 200 feet, determine the offsets from the tangent to the midpoint...
2. Given a sag vertical curve connecting a -1.5% grade with a +2.5% grade on a rural arterial highway, use the rate of vertical curvature and a design speed of 70 mi/h to compute the elevation of the curve at 100 ft stations if the grades intersect at station (475+00) at an elevation of 300.00 ft. Identify the station and elevation of the low point.
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station Tangent Elevation Tangent Offset В VC 45+00 45+50 46+00 PVI 678.14 46+18.47 46+50 47+00 47+50 EVC I. gl=+4.3%, g2 =-3.196, L = 300, 2. Calculate stations for BVC and EVC and insert into table 3. Calculate station for high/low point and insert into table (this will be located between stations already entered in table, and not yet highlighted). 4. Calculate ALL tangent elevations, tangent...
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