![6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.- 1 134.50, gi-30%, g2+ +1.4%, L :300, what is the station and elevation of the BVC? a) 17+00; 1138.00 17+00; 1139.44 h9+50; 1142.00 d) 19+50; 1138.00 7. Based on the following Vertical Curve information (units in ft.): PVI Sta 1 134.50, gi .-30%, g2+ +1.4%, L . 500, what is the elevation on the curve at Sta. 23 22+00, PVI Elev. a) 1138.49 b) 1137.41 c) 1136.89 d) 1137.25 8. Based on the following Vertical Curve information (units in ft.): PVI Sta. 22+00, PVI Elev. 1134.50, g1--30%, g2 +1.4%, L . 500, what is the station of the High/Low Point? a) 21+09.09 b) 22+00.00 c) 23+00.00 d) 22+90.91 9. Based on the following Vertical Curve information (units in ft.): PVI Sta.-22+00, PVI Elev. 1134.50, g1--3.0%, g2+ +1.4%, L-500, what is the elevation of the High/Low Point? a) 1136.89 b) 1136.45 c) 1136.74 d) 1136.53 10. Based on the following Vertical Curve information (units in ft.): PVI Sta. 1134.50, g]s-3.0%, g2 +1.4%, L-500, What is the elevation of the EVC? 22+00, PVI Elev.- a) 1137.41 b) 1138.00 c) 1142.00 ) 1141.24](http://img.homeworklib.com/questions/fc1dd1d0-61c2-11ec-9300-a3c813795ef5.png?x-oss-process=image/resize,w_560)
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6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.-...
(A) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00...
(A) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00 ft, BVC Station = 10+00.00, BVC Elev = 5000.00 ft. EVC Station = ? (b) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00 ft, BVC Station = 10+00.00, BVC Elev = 5000.00 ft. EVC Elevation = ? (D) For an equal tangent vertical curve g1 = -4%, g2 = +3%, L = 200.00 ft, BVC Station =...
4. Based on the following information: VPI: Sta: 87+25.00 Elev: 115.78 ft gi-3.5% Obstruction: St...
4. Based on the following information: VPI: Sta: 87+25.00 Elev: 115.78 ft gi-3.5% Obstruction: Sta: 90+35.00 Elev: 152.39 ft Clearance: 20.00 ft What is the station and elevation of BVC. (10pts) What is the station and elevation of EVC. (10pts) What is the station and elevation of LP. (10pts)
4. Based on the following information: VPI: Sta: 87+25.00 Elev: 115.78 ft gi-3.5% Obstruction: Sta: 90+35.00 Elev: 152.39 ft Clearance: 20.00 ft What is the station and elevation of BVC. (10pts)...
CM208 CONSTRUCTION SITE SURVEYING HW #6 (100pts) 1. Based on the following information: A (N1200.00, E1850.00)...
CM208 CONSTRUCTION SITE SURVEYING HW #6 (100pts) 1. Based on the following information: A (N1200.00, E1850.00) B (N2100.00, E2875.00) C (N1900.00, E4000.00) Find the radius (R) of the circular are passing through points ABC. (20pts) Find the coordinates of the center (O). (10pts) 2. Based on the following information: A (N350.00, E450.00) B (N875.00, E850.00) C(N1100.00, E200.00) Evaluate the bearings and distances of traverse ABC. (20pts) 3. Based on the following information: L=7 stations BVC EVC -1.5% +2.0% PVI Sta:...
6) Given the following vertical curve data: PVI at 18+00; L-500 ft: gi-3.5 %; g,--1.5 %;...
6) Given the following vertical curve data: PVI at 18+00; L-500 ft: gi-3.5 %; g,--1.5 %; elevation of PVI-723.86 ft, compute the elevation and station of the curve high point and the elevations of the stations listed in the table below. (10 pts) Station of High point Elevation of High Point Station 15+50 16+00 17+00 18+00 18+10 19+00 20+00 20+50 Elevation
12-5. What is the sta. and elev. for both the BVC and the EVC of vertical curve that joins a back tangent of +0.50% and tangent of +3.65%. The sta, and elev. of the PVI are 21 + 73.50 8 a forward...
12-5. What is the sta. and elev. for both the BVC and the EVC of vertical curve that joins a back tangent of +0.50% and tangent of +3.65%. The sta, and elev. of the PVI are 21 + 73.50 8 a forward Ans.: (a.) BVC: sta. 15+85; elev. 76.50 EVC: sta. 26+85; elev. 93.58 (b.y BVC: sta. 15+85; elev.- 70.75 EVC: sta.- 26+85; elev. 93.58 (c.) BVC: sta. 15+85; elev. - 76.50 EVC: sta.- 21+45; elev. 53.42 (d.) BVC: sta....
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at...
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at station 40+00.00 at an elevation of 100.00 ft. The design speed is 70 mi/h. If the length is 1084 ft, determine: (b) The station of the BVC (3 pts (c) The elevation of the BVC (3 pts (d) The station of the EVC (3 pts) (e) The elevation of the EVC (3 pts) (1) The station of the highest point on the curve (4...
Find L please! -3 % high elevation on curve is 206.00 Find L. 2. PC station...
Find L please!
-3 % high elevation on curve is 206.00 Find L. 2. PC station = 10+00.00 PC elev = 200.00 G1=+2% G2=-3% at station 15+00 elevation must be 205.00 Find L 3. PI elev 185.00 GI=+2% G2--3% high elevation on curve is 176.00 Find L 4. P1 station = 16+25.00 P1 elev = 185.00 G1 +2% G2--3% at station 15+00 elevation must be 175.00 Find L
Problem 4 A 500 ft long sag vertical curve passes under a bridge at station 82+45....
Problem 4 A 500 ft long sag vertical curve passes under a bridge at station 82+45. The beginning of vertical curve (BVC) is at station 81+00. A-3.6% curve meets a +4.4% curve at the point of vertical intersection (PVI), which is at elevation 425.38 ft. What is the elevation of the point on the curve under the bridge? Problem 5 The grade into a vertical sag curve is -2%. The curve length is 1,400 ft. The grade out of the...
9-(10 pts) Stake elevation at each station along the curve, given the below g1-2.5 21.0 Sta ation of BVC 25+50: ength of parabolic curve 500 ft Elevation of BVC 800 ft 9-(10 pts) Stake eleva...
9-(10 pts) Stake elevation at each station along the curve, given the below g1-2.5 21.0 Sta ation of BVC 25+50: ength of parabolic curve 500 ft Elevation of BVC 800 ft
9-(10 pts) Stake elevation at each station along the curve, given the below g1-2.5 21.0 Sta ation of BVC 25+50: ength of parabolic curve 500 ft Elevation of BVC 800 ft
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station...
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station Tangent Elevation Tangent Offset В VC 45+00 45+50 46+00 PVI 678.14 46+18.47 46+50 47+00 47+50 EVC I. gl=+4.3%, g2 =-3.196, L = 300, 2. Calculate stations for BVC and EVC and insert into table 3. Calculate station for high/low point and insert into table (this will be located between stations already entered in table, and not yet highlighted). 4. Calculate ALL tangent elevations, tangent...
4. Based on the following information: VPI: Sta: 87+25.00 Elev: 115.78 ft gi-3.5% Obstruction: Sta: 90+35.00 Elev: 152.39 ft Clearance: 20.00 ft What is the station and elevation of BVC. (10pts) What is the station and elevation of EVC. (10pts) What is the station and elevation of LP. (10pts)
4. Based on the following information: VPI: Sta: 87+25.00 Elev: 115.78 ft gi-3.5% Obstruction: Sta: 90+35.00 Elev: 152.39 ft Clearance: 20.00 ft What is the station and elevation of BVC. (10pts)...
CM208 CONSTRUCTION SITE SURVEYING HW #6 (100pts) 1. Based on the following information: A (N1200.00, E1850.00) B (N2100.00, E2875.00) C (N1900.00, E4000.00) Find the radius (R) of the circular are passing through points ABC. (20pts) Find the coordinates of the center (O). (10pts) 2. Based on the following information: A (N350.00, E450.00) B (N875.00, E850.00) C(N1100.00, E200.00) Evaluate the bearings and distances of traverse ABC. (20pts) 3. Based on the following information: L=7 stations BVC EVC -1.5% +2.0% PVI Sta:...
6) Given the following vertical curve data: PVI at 18+00; L-500 ft: gi-3.5 %; g,--1.5 %; elevation of PVI-723.86 ft, compute the elevation and station of the curve high point and the elevations of the stations listed in the table below. (10 pts) Station of High point Elevation of High Point Station 15+50 16+00 17+00 18+00 18+10 19+00 20+00 20+50 Elevation
12-5. What is the sta. and elev. for both the BVC and the EVC of vertical curve that joins a back tangent of +0.50% and tangent of +3.65%. The sta, and elev. of the PVI are 21 + 73.50 8 a forward Ans.: (a.) BVC: sta. 15+85; elev. 76.50 EVC: sta. 26+85; elev. 93.58 (b.y BVC: sta. 15+85; elev.- 70.75 EVC: sta.- 26+85; elev. 93.58 (c.) BVC: sta. 15+85; elev. - 76.50 EVC: sta.- 21+45; elev. 53.42 (d.) BVC: sta....
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at station 40+00.00 at an elevation of 100.00 ft. The design speed is 70 mi/h. If the length is 1084 ft, determine: (b) The station of the BVC (3 pts (c) The elevation of the BVC (3 pts (d) The station of the EVC (3 pts) (e) The elevation of the EVC (3 pts) (1) The station of the highest point on the curve (4...
Find L please!
-3 % high elevation on curve is 206.00 Find L. 2. PC station = 10+00.00 PC elev = 200.00 G1=+2% G2=-3% at station 15+00 elevation must be 205.00 Find L 3. PI elev 185.00 GI=+2% G2--3% high elevation on curve is 176.00 Find L 4. P1 station = 16+25.00 P1 elev = 185.00 G1 +2% G2--3% at station 15+00 elevation must be 175.00 Find L
Problem 4 A 500 ft long sag vertical curve passes under a bridge at station 82+45. The beginning of vertical curve (BVC) is at station 81+00. A-3.6% curve meets a +4.4% curve at the point of vertical intersection (PVI), which is at elevation 425.38 ft. What is the elevation of the point on the curve under the bridge? Problem 5 The grade into a vertical sag curve is -2%. The curve length is 1,400 ft. The grade out of the...
9-(10 pts) Stake elevation at each station along the curve, given the below g1-2.5 21.0 Sta ation of BVC 25+50: ength of parabolic curve 500 ft Elevation of BVC 800 ft
9-(10 pts) Stake elevation at each station along the curve, given the below g1-2.5 21.0 Sta ation of BVC 25+50: ength of parabolic curve 500 ft Elevation of BVC 800 ft
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station Tangent Elevation Tangent Offset В VC 45+00 45+50 46+00 PVI 678.14 46+18.47 46+50 47+00 47+50 EVC I. gl=+4.3%, g2 =-3.196, L = 300, 2. Calculate stations for BVC and EVC and insert into table 3. Calculate station for high/low point and insert into table (this will be located between stations already entered in table, and not yet highlighted). 4. Calculate ALL tangent elevations, tangent...
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