Question

9-(10 pts) Stake elevation at each station along the curve, given the below g1-2.5 21.0 Sta ation of BVC 25+50: ength of parabolic curve 500 ft Elevation of BVC 800 ft

Answer 1

In this problem, we can solve by elevation of the vertical curve by the equation of a parabola

25 length of Pora blic carve 500 ff- PVエ(point on, inersectim Eleva,on of ELevohon ot ENC 8(S) 0 3- 75 m the squdii bola the. nesu vesticcurve 3,-3, y= elevadion on the verti case carve at Curve distonce m evc

FiNen Nale,we get s 00 80O Assume. sttion mtes val is so Sect cna ot

m point 8e 1-3.sx6sx2. | 0102.sz. RL of eve -S2- RI of Port on veytica, Cuwe 800 2 0.08 귀n 801. 1625 80 2, 1.5 0 802. 9625 3-75 804, 0625 | 3-IS 3.4' s 29450- 80 4-y 804-162-5

ENC 9 (Io) 켜 le

chainage	point	distance (ft)	elevation (ft)
25+50	BVC	0	800
26	1	50	801.1625
26+50	2	100	802.15
27	3	150	802.9625
27+50	4	200	803.6
28	5	250	804.0625
28+50	6	300	804.35
29	7	350	804.4625
29+50	8	400	804.4
30	9	450	804.1625
30+50	10	EVC	803.75