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Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for...

Enter your answer in the provided box. Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 × 10−8 at 700°C: 2 H2S(g) ⇌ 2 H2(g) + S2(g) If 0.35 mol of H2S is placed in a 3.0−L container, what is the equilibrium concentration of H2(g) at 700°C?

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This question is solved by using simple concept of chemical equilibrium which involves the expression of equilibrium constant and its value to calculate the equilibrium concentration.

The answer is given in the image,

Ansules :- 2H2569) 32H219) + S2(g) [H2566 = 0.35 = 0.1167 M so 2H25C%) 242691 + 52692 0.1167-22 23 2 am 0.1167 because ke is

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