Question

Part BShow your work on all free-response questions, Be sure to use proper units and significant figures your final answers. For any multiple-choice questions, circle the letter of the one best answer (unless answer is asked for). more than a P P P. P P P 1. Two point charges, Q=-2.5 nC and Q Five equipotential surfaces (dashed curves above) are drawn for you in the diagram. (Assume that V= 0 at r = away from the charges.) +2.5 nC, are fixed in space as shown above, forming an equal dipole. a. (2 pts.) Suppose that the five equipotential lines shown above correspond to potentials of -200. v,-100. V, 0 V, +100. V, and +200. V. Clearly label the corresponding equipotentials with these five values. b. (2 pts.) Draw between 8 and 12 electric field lines on the diagram above. Include directional arrowheads on ALL of your field lines. c. (4 pts.) Suppose that a proton is moved from a point located on the -200.-volt equipotential line to a +200-volt equipotential line. (The proton starts and ends at rest.) How much energy does this require? Show your work. Express your final answer in electron-volts: point on the

please answer questions a-d compeltely and show your work

Answer 1

The equipotential surface is levelled with the corresponding voltage (b) the electric filed is also shown in the figure the electric field for the equipotential surface perpendicularly (c) a proton is moved from a point on - 200 volt equipotential surface to + 200 v equipotential surface then the energy required W = 200 q - (- 200 q) = 400 times 1.6 times 10^19 Joule = 400 ev (d) now a proton is moved from the point p_1 to p_5 these two points are lying on the same equipotential surface hence to move a proton from p_1 to p_2, the work done will be zero Therefore no energy will required