Question

-/1 points V KATZPSEF1 5.P.076. My Notes Ask Your Teacher v Jamal and Dayo are lifting a large chest, weighing 335 lb, by using the two rope handles attached to either side. As they lift and hold it up so that it is motionless, each handle makes a different angle with respect to the vertical side of the chest (see figure below). If the angle between Jamal's handle and the vertical side is 25.0° and the angle between Dayo's handle and the vertical side of the chest is 30.0°, what are the tensions in each handle? (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) FT, = FT = 30.0° Need Help? Read It

Answer 1

fra - Fig sino F, tin 25, Mass of the block, m= 335 lb. 335 2-205 &m= 151-93kg. I dension of the strings are Fip and fig which make angles 30 and 25° respectively with the restical, then at equilibrium - I cosso & Fig cos 25° = mg. - sig and Firsin 30 - & Fig sin 25° = 0. – in

From - Fap. + fg cos 25" - 151.93 x 9.8. 5 Ft. B + Fly x0.906 = 1488.91, From (ii) - Fro: [ - t 0.423 F75 = 0 .. 5) Fro = 2x0.423 Fic. = 0.845 Ft using in - 0.854 Ft; x + Bog 0.906 Fts = 1488.91. 1638 Fts = 1438.91. Fry 908-98 N. And, from (i) - FT, = 0.845 Fto = 768.09 M, Fag = 908.98 M & Fro = 768.09 N.