Question

According to a study done by UCB students, the height for Martian adult males is normally distributed with an average of 67 inches and a standard deviation of 2.3 inches. Suppose one Martian adult male is randomly chosen. Let X = height of the individual. Round all answers to 4 decimal places where possible.

a. What is the distribution of X? X ~ N(,)

b. Find the probability that the person is between 62.1 and 65.3 inches.  

c. The middle 20% of Martian heights lie between what two numbers?
Low:  inches
High:  inches

Answer 1

a. What is the distribution of X? X ~ N(,)

Answer: X ~ N(67,2.3)

b. Find the probability that the person is between 62.1 and 65.3 inches.  

Answer: 0.2133

c. The middle 20% of Martian heights lie between what two numbers?
Low: 66.4173 inches
High: 67.5827 inches

NN ,) X a) and is stendard deuiahin whre mean is X NC67, 9-3) b) Probability that and behw een the is person inches 65-3 6a.1 inches that Now Cre we l67 F2.3 PC 62.1 X 65.3) 62.16 - 2.130 434782 O.016568 2-3 O.73912642y 65 3-67 - 2-3 calulato by of ZSCone value The extel Cemmand uning Noamscist (-2.130424182)

O.912346 0-2133 CROnded to four decimas places) finis aio found answer Can diredey in end Use Cammand Nom.dist 67,3-3,63)gives Cutpt OO16562 Norm dist67,2.3,65.3) gies out put 0 2914 Then 0.9 9914-06568 F0.9132 Subtnact the values o %of Marhin heiqut Lie what C) The behween middle mumbeu? TRe ange guen y 10. O8 O25335 O.a533 ut (Z1) Range is 67 (0.953g )3 67 (0.25 33 )2.3- 66.4173 67 C0.953?) 267.57 limit Lower limit Upper 20 % Range i 66.4173, 67. 5227)

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