Question

Suppose a survey of 24 people asked how many books they have read in 2018. The results are shown in the table below.

Number of Books Read

4	3	8	15	10	0	5	5
7	6	7	1	8	3	3	1
6	2	0	3	7	12	20	2

Step 3 of 7:

Which is a better measure of center for this data? Why?

Give the 5 Number Summary of this data.

What is the interquartile range (IQR) of this data?

What is the standard deviation for this data?

Which is the better measure of dispersion? Why?

A. IQR. It is easier to find.

B. IQR. The boxplot shows outlier(s) and IQR is a resistant measure of dispersion.

C Standard deviation. It goes with mean which makes it better.

D. Standard deviation. The boxplot shows no outlier(s) so it is better to use in this case.

Answer 1

A. Mean is the better measure of central tendency because it consider the all data values B. Q1=1st quartile =median for the 1st half of the data set Q2=median =middle value of the data set Ifn is odd median is (n+1)/2 th term if n is even mean of middle two terms Q3 =3rd quartile =median of the 2nd half of the data set Given n= 24 5-stastitsical summery are Q1 =2.5 median=5 Q3 =7.5 Min = 0 Max=20 C. Inter quartile range IQR=Q3-Q1 = 7.5-2.5=5.0

D. Mean = x/n= 138/24 =5.75 Standard deviation s= /(x- ² v n-1 234.5 -=4.8207 24-1 E. Standard deviation is the better measure of depreciation than IQR because is take all values Option C is correct Box plot is Min Q1 Q2 Q3 Max 0 2.5 5 7.5 20 от 10 15 Box plot