A survey was conducted that asked 1011 people how many books they had read in the past year. Results indicated that
x overbarx equals=13.6
books and s equals=16.6
books.
Construct a 90% confidence interval for the mean number of books people read. Interpret the interval.
Construct a 90% confidence interval for the mean number of books people read and interpret the result.
Given that,
= 13.6
s =16.6
n = 1011
Degrees of freedom = df = n - 1 =1011 - 1 = 1010
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
t /2,df = t0.05,1010 =1.646
Margin of error = E = t/2,df * (s /n)
= 1.646* (16.6 / 1011) = 0.86
The 90% confidence interval is,
- E < < + E
13.6 - 0.86< < 13.6+ 0.86
12.74 < < 14.46
(12.74,14.46 )
LOWER LIMIT 12.74 TO
UPPER LIMIT 14.46
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