6. A distance of 5.00 cm is measured between two adjacent nodes of a standing wave...

Question

Question

6. A distance of 5.00 cm is measured between two adjacent nodes of a standing wave on a 20.0-cm-long string. harmonic number

Answer 1

Answer #1

- na = L (Length of string) nxs= 20 [n=4 4th harmonic Velocity 875 = 223.607mls A F=2236.074

Answer 2

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