Question

mework Saved 5 attempts left Check my work Click in the answer box to activate the palette. Fluorine is so reactive that it forms compounds with materials inert to other treatments. When 0.266 of platinum is heated in fluorine, 0.422 g of a dark red, volatile solid forms. What is its empirical formula? < Prey 5 of 25 l Next >

Answer 1

Let the formula of dark red compound be of the form PtFx (where x is the number of fluorine attached with each Pt)

Molar mass of Pt = 195 g/mol

Molar mass of F = 19 g/mol

Number of moles of Pt = Mass/Molar mass = 0.266/195

This must be equal to number of moles of product formed

Moles of Product formed = (mass)/(molar mass) = 0.422/(195+19x)

Solving the equation for x we get

0.266/195 = 0.422/(195+19x)

195 + 19x = 309.36

19x = 114.36

x = 114/19 = (approximately equal to 6)

Hence the empirical formula of the compound will be PtF6

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