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Question

Question

Answer 1

Answer #1

Answer

340g

Explanation

Freezing point depression of water is calculated by the following formula

∆T_f = K_f × b × i

where,

K_f = freezing point depression constant, 1.86℃/m

b = molality of solute , ?

i = Van't Hoff factor , 2

5.0℃ = 1.86℃/m × b × 2

b = 1.344m

molality = moles of solute per kilogram of solvent

moles of NaCl required for 4.3kg of water = 1.344mol/kg×4.3kg = 5.7792 mol

mass = number of moles × molar mass

mass of NaCl required = 5.7792mol × 58.44g/mol = 340g

Answer 2

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