On reactant side we have:
12 C-H bond
2 C-C bond
7 O=O bond
On product side we have:
8 C=O bond
12 O-H bond
Use:
Delta H = BE(reactant) - BE(product)
=12*BE(C-H) + 2*BE(C-C) + 7*BE(O=O) - 8*BE(C=O) - 12*BE(O-H)
= 12*414 + 2*347 + 7*498.7 - 8*745 - 12 * 460
= -2327.1 KJ
Answer: -2327.1 KJ
Saved omework 2 attempts left Check my work Enter your answer in the provided box. Predict the enthalpy of reaction...
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