1H NMR data:
NMR peak value (ppm) |
Protons |
Indication |
3.8 |
2H, doublet |
CH2 attached to oxygen |
2.0 |
3H, singlet |
CH3 attached to carbonyl |
1.9 |
1H, multiplet |
CH attached to two CH3 |
0.9 |
6H, doublet |
Two equivalent CH3 attached to CH |
13C NMR data:
NMR peak value (ppm) |
Indication |
170 |
Carbonyl carbon, ester |
70 |
Carbon attached to oxygen |
27 |
Aliphatic carbon |
20 |
Aliphatic carbon |
18 |
Two Aliphatic carbon |
IR data:
IR peak (cm-1) |
Indication |
2873 |
Aliphatic C-H |
1744 |
C=O stretch Probably ester |
1238 |
C-O stretch |
All above data confirms following structure
Given the C-NMR, H-HNMR and IR spectrum, what is this compound? It has a melting point of 134 degrees celsius and is in deuterated chloroform solvent. #40-B C NMR 0.5 abundance 18010 170.0 1600 150.0 140.0 130.0 1200 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 173.1580 147.4781 140.9673 129.7718 118.2608 9ISSILL 77.1310 76.7103 18.8397 X: parts per Million : 13C CD bundance 7.0 8.0 X: parts per Million: 1H 7.3613 7.3270 7. 98 7.2766 6.2053 6.1962 6.1824...
Need help answering questions 5 (a, b, & c), 6, & 7. Thank you. erimental data: a. Calculate the theoretical yield of product from today's experiment. Show your work (1 point) o.sgol = 0.00179 mol 278.775 g/mol lol = 0.0ol 79 mol x 260.33 ghnol = 0.466 g g b. Report the mass of synthesized product (0.25 point): 260.33 c. Report the melting range of synthesized product (0.5 point): 160-163°C d. Calculate the percent yield of today's experiment. Show your...