Question

How many grams of Na2CO3 would be needed to react with 750mL of 0.250M HCI solution? Na2CO3 + 2HCl --> H2O + CO2 + 2Naci 39.8g Na2CO3 09.948 Na2CO3 19.9g Na2CO3 25.0g Na2CO3

Answer 1

please rate

volume of HCl = 750 mL = 0.75 L : 1000 mL=ILI concentration of HCl = 0.250 M moles of HCl = concentration (M) X Volume (L) = 0. 250 M X 0.75 L = 0.1875 mol = Na2CO3 + 2HCl H2O + CO2 + 2Nach 2 moles of HCl react with I mole of Na2CO3 0.1875 moles of HCl react with moles of Na2CO3 = Imol X 0.1875 mol 2 mo! = 0.09375 mol moles of Na2CO3 needed = 0.09375 mol molar mans of NaCO3 = 105.99 g/mol mans of Na2CO3 needed = moles x molar mass. = 0.09375 mol X 105.99 g/moj - 9.94 g Answer Hence, option I is correct