How many grams of Na2CO3 (FW = 106) are needed to prepare: a) 250 mL of...

Question

Question

How many grams of Na2CO3 (FW = 106) are needed to prepare:

a) 250 mL of 6.0 M solution

b) 250 g of a 10% solution

Answer 1

Answer #1

a.

volume of solution = 250ml

molarity of solution = 6M

FW of Na2CO3 = 106g/mole

molarity = mass of Na2CO3*1000/FW of Na2CO3* volume of solution in ml

6 = mass of Na2CO3*1000/106*250

mass of Na2CO3 = 6*106*250/1000 = 159g >>>>>answer

b.10% Na2CO3 means 10g of Na2CO3 in present in 100g of solution

100g of solution contains 10g of Na2CO3

250g of solution contains = 10*250/100 = 25g of Na2CO3 >>>>answer

Answer 2

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