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T-Mobile Wi-Fi 11:57 AM Close Homework for April 9.pdf Homework for Class #3-April 9-(20 points) Do the problems 0ค separate
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Answer #1

Since there are multiple questions, I would limit myself to answering the first questuon.

It is a simple case of compound interest.

A = P (1+r)^n

Where

A is amount, P is principal,r is rate of interest and n is number of time periods

In first case, total amount is 1,000* (1+0.08)^3 = 1259.71

In second case, the bank does quarterly compounding, hence rate per quarter is = 8/4 = 2% compounded over 3*4= 12 quarters

Hence total amount = 1,000*(1+0.02)^12 = 1268.24

In third case, since the amounts are invested over 3 years, the first installment gets compounded thrice while the second and third installments are compounded twice and once respectively.

Hence total amount :

Year 1 amount (1000/3)*(1.08)^3 = 419.90

Year 2 amount (1000/3)*(1.08)^2 = 388.8

Year 3 amount (1000/3)*1.08 = 360

Hence total maturity amount = 1168.7

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