Ans. A % (w/w) concertation is expressed as mass of solute per 100.0 g of solution.
# Mass of solution = Mass of water (solvent) + Mass of Na2CO3 (solute)
= 245.0 g + 25.0 g
= 270.0 g
Now,
% Na2CO3 (w/w) = (Mass of solute / Mass of solution) x 100
= (25.0 g / 270.0 g) x 100
= 9.259 %
Calculate the mass percent if 25.0 grams of sodium carbonate is dissolved in 245 grams of...
Calculate the mole ratio of sodium carbonate to water if 0.4 grams of sodium carbonate combined with 0.6 grams of water.
Calculate the percent mass by volume for 19.0g of a lithium carbonate dissolved in 200.0 mL of total volume.
6.52 grams of sodium hydrogen carbonate is weighed into a 150 ml beaker and dissolved in 100 ml of deionized water. The solution is then quantitatively transfer to a 250.0 mL volumetric flask and filled to the line with deionized water. What is the molarity of hydrogen carbonate in the volumetric flask?
A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered out, the HCl was neutralized by adding sodium carbonate. The resulting precipitate was pure calcium carbonate (with the fillers removed). The solid calcium carbonate was collected on a watch glass that had a mass of 46.719 g when empty. After the calcium carbonate had been allowed to dry, the mass of the watch glass plus product was found...
A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered out, the HCl was neutralized by adding sodium carbonate. The resulting precipitate was pure calcium carbonate (with the fillers removed). The solid calcium carbonate was collected on a watch glass that had a mass of 46.719 g when empty. After the calcium carbonate had been allowed to dry, the mass of the watch glass plus product was found...
The standard enthalpies of formation for solid sodium carbonate, aqueous sodium ion, aqueous carbonate ion, and liquid water are -1131 kJ, -240.1 kJ, -677.1 kJ, and -285.8 kJ, respectively. If 5.00 g of solid sodium carbonate at 25.0°C is dissolved in 50.0 g of liquid water, also initially at 25.0°C, immediately after dissolution is complete will the temperature of the resultant solution be greater than, less than, equal to, or cannot be determined compared with 25.0°C? Justify your choice.
The standard enthalpies of formation for solid sodium carbonate, aqueous sodium ion, aqueous carbonate ion, and liquid water are -1131 kJ, -240.1 kJ, -677.1 kJ, and -285.8 kJ, respectively. If 5.00 g of solid sodium carbonate at 25.0°C is dissolved in 50.0 g of liquid water, also initially at 25.0°C, immediately after dissolution is complete will the temperature of the resultant solution be greater than, less than, equal to, or cannot be determined compared with 25.0°C? Justify your choice.
Chem 143 - Lab 46) CALCULATE THE THEORETICAL YIELD Grams of sodium carbonate used Moles of sodium carbonate used Grams of calcium chloride used Moles of calcium chloride used Moles of precipitate expected Theoretical yield of precipitate in grams Actual yield of precipitate in grams Percent yield 5.6 Show detailed work for percent yield. Page 4 of 4 Chem 143 - Lab Pre-lab Exercise Show the details of each calculation to get full credit 1. Magnesium oxide, a white powdery...
A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered out, the HCl was neutralized by adding sodium carbonate. The resulting precipitate was pure calcium carbonate (with the fillers removed). The solid calcium carbonate was collected on a watch glass that had a mass of 46.719 g when empty. After the calcium carbonate had been allowed to dry, the mass of the watch glass plus product was found...
If 10.0 grams of sodium sulfate are dissolved in 90.0 grams of water, the percent (w/w) sodium sulfate in the resultant solution is: Select one: O a: 10.0 % (w/w) o b. 9.00 % (w/w) O c. 90.0 % (w/w) d. 1.0 % (w/w) e. 9.0 M