Please find the solution from following pictures
B. Design an interior one-way slab considering the given loading. The weight of the slab is...
Design an interior one-way slab for the figure and load shown below. Given: fc = 4000 psi, fy 60,000 psi The only dead load is the weight of the slab Do not use the ACI Code's minimum thickness for deflection Table 7.3.II Steel percentage p 0.0143 is given in the figure. Finally sketch the slab and show the approximate bar location ρ=0.0143 24
Design interior one-way slab for the situation shown. Concrete weight = 150 lb/ft^3 f_y= 60,000 psi, f_c= 4,000 psi. Do not use the ACI Code’s minimum thickness for deflections. Assume: h= 7.5 in, b= 12 in, d= h-0.75-(0.25) steel percentages are given on the figures. The only dead load is the weight of the slab WL150 psf im -24 ft WL150 psf im -24 ft
question 9 (a) 9 Design interior one-way slabs for the situations shown. Concrete weight 150 lb/ft3, fy= 60,000 psi, and f c= 4000psi. Do not use the ACI Code's minimum thickness for deflections (Table 4.1). Steel percentages are given in the figures. The only dead load is the weight of the slab. a) WL150 psf 24 ft
2-You are given the task of designing a simply supported one-way slab, with a 13 feet span. The slab supports a live load of 200 psf. Use fc=3,000 psi, fy=60,000 psi. Provide a sketch of your design. 1 - Provide three (3) provisions about bar choosing/placing in concrete slabs, which you would need to consider as a structural engineer. Discuss the rationale behind each item. 2- You are given the task of designing a simply supported one-way slab, with a...
Assume normal concrete weight (wc = 143 lb/ft) with specified compressive strength fc = 4,000 psi, and steel Grade 60 (fy = 60,000 psi). For design loads assume dead load wd = 30 lb/ft? (excluding self-weight) and live load we = 100 lb/ft. Finally assume that the steel percentage ratio is equal to p= 0.18fc/fy. Design an interior one-way simply supported slab with a 15 ft span using the above assumptions. Show sketches of one-way slab cross section, including reinforcing...
Problem 3 Assume normal concrete weight (wc = 143 lb/ft) with specified compressive strength fc = 4,000 psi, and steel Grade 60 (fy = 60,000 psi). For design loads assume dead load wd = 30 lb/ft? (excluding self-weight) and live load wų = 100 lb/ft. Finally assume that the steel percentage ratio is equal to p= 0.18fc'/fy. Design an interior one-way simply supported slab with a 15 ft span using the above assumptions. Show sketches of one-way slab cross section,...
Design a simple-span, one-way slab to carry a uniformly distributed live load of 375 psf plus the self-weight of the slab. The span is 10-ft., center-to-center of the supports. Assume fe' = 4,000 psi and fy = 60,000 psi. Design per foot of width. Use #5 bars for both longitudinal and temperature and shrinkage reinforcement. (30 pts.)
Problem Two: The beam shown below part is for an interior span and is cast monolithically with a one-way slab. The clear span for the beam is 30 feet, and the clear spacing between beams is 10 feet. (a) Reinforcement is shown for the positive moment region. Determine if the beam is adequate to support a uniformly distributed, factored load of 5 k/ft. (b) Design the slab reinforcement for the positive moment region using a factored load of 500 psf....
For Problems 1 and 2, design rectangular sections for the beams. Loads and Density values are shown. Beam weights are not included in the loads shown. Show sketches of cross sections, including bar sizes, arrangement, and spacing. Assume concrete weighs 150 lb/ft3, fy = 60,000 psi, and fc′ =4000 psi, unless given otherwise. 2. Design a cantilever beam. The loading cases are shown in Figure 2: Wp = 3 k/ft, w, = 1 kft MITIMIZ 12f- Use p= 0.1852 Figure...
Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight Concrete fy=60,000 psi, and Es 29 X 105 psi. 30 in. (762 mm) 3 in. 3 No. 10 3 No, 9 2을 in. 12 in. (304,8 mm) in. -10 in.- (b) (a) 15 in. (wu (533.4 mm) Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight Concrete fy=60,000 psi,...