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Problem 3 Assume normal concrete weight (wc = 143 lb/ft) with specified compressive strength fc = 4,000 psi, and steel Grade

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Given concrete weight = wea14316lfts. fel a uksi ty=60ksi worzo lopft (excluding self weight) When 100 lb/ft2 Sean L = 15, hطوسیا Moment my - (0.1228) 15x15 - 08882 – 3.45 Kft. - 41.44 kiin 0.18 fc - 0.18 (4) Given a 60 e 20.012 Main steel : eregbdReinforcement pattern: mainsteel it maximum spacing min (3h, 18) = (3x5, 18) manimum fpally in main steel = 151 transverse#3@ 12 ec. vey #s@6th le

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