Question

1. What do “3” and “p” imply in 3p? How many orbitals (ml values) are there in a 3p sub-level (draw them and name them)? What are the possible values ​​of the quantum spin number of the electron?

2. Give the values ​​of the quantum numbers associated with the following orbitals: a) 2p2, b) 3s2, c) 5d8.

3. Point out which of the following sets of quantum numbers are unacceptable and explain why:
    a) (1, 0, 1/2, +1/2), b) (3, 0, 0, +1/2), c) (2, 2, 1, + 1/2), d) ( 4, 3, -2, + 1/2), e) (3, 2, 1, 1).

4. Enter the electronic configuration of:
    a) The phosphorus atom present in phosphorous acid.
    b) The chlorine atom in iron chlorate III.
    c) The manganese atom in potassium permanganate.

Answer 1

To address any election in any atom, there are four Quantam number 4 principle Quantum no. ( n u r b It identifies the shell in which electm is revolving. The value of n is a positive Integer with the value , n=1, 2, 3, ...n Azimuthal Quantum no. El): It defines the shape of orbital, for a given value of n, I can have a values ranging from o to not. So value of I can be 0, 1, 2, 3.... Sub-shell corresponding to different value of f. Value of l: 0111213 Notation for sub-shell: Sed f @ magnetic duantum no.fm): - It gives information about the spatial arrangement of the orbital with respect to Co-ordinat anus. for a given sub-shell, I there are alth Values of m are possible.

these values are: - ma-p, -(4-1),-(4-2), --.0, 1 --(4-2) (4-1), f. for example, if we consider t=2 then possible values of m are,- 2,-1, 0, 4, +2 ( spin Quantum no. (s): - Ion It describe the orientation of election relative to choosen anis. Elections are in two spin state. Elections can have two possible values of spin Quantum no.. one is +2. for spin up and second is the for spin down. I Example fond Consider s-orbital, there are two electrons. (T), so, for a spin auantum no is the s for t spin Quantums no is the According to given suestion, in ap a 3 is principle duautum no. ie: n=3 (Shell no.) thel and p is the natation for orbitul type a Because there are four types of orbitul we have used in obemistry.

sed and, f. Orbital name No. of orbital uleo 7. So 3 in the 3p sub-level, there orbitul , because p has 3 are orbitals. 2222222LLLLLLLLLLLLLIIIIIIIII 3Pre 3py 312 Structure for 3p sub-level 3P2 Luantum no. of 3p. possible values of n = 3 1 = 1 (for P, d = 1) m = -1, oth S = -1/2, +4₂

m = -2 ott 2px 2py 2 P2 Quantum no. for 1st electrom, n= a f = 1 (for P, d = 1) ma-1 S=+1/2 (spin up) Quantum no. for and electron. n=2 f=1 m= 0 S=+/2 (splno) m: - 1 0 tl b) 352 1st & 1 and é e 85 Quantum Mo. for 1st election. po ( for 5, 1:0) s = t42 (spin up) mo

Quantum Mo for and election, n=3 f = 0 m=o s=-1/2 (spin down) c) 508 m = -2 -1 oth +2 possible quantum Mos. n = 5 (for all elections) f=2 ( for d, 1=2) m=it well ranges from 2 to +2 ie, -2,-1, 0, +2, +2 S= +42 for spin up. or - H₂ for spin down. Ⓡ a) (1,0,4/2, +12) Here n=1 (possible) f=0 (possible because it is corresponday) to s) m = 1/2 (It is not possible because the value of n should be Integer and should be sauges for tl to - f.

So, (1,0 ,f is not a possible Quantum . b) (3,0,0, +4/2) n=3 (possible = 0 (Corresponding to s) (possible) m=0 (possible) S = +1% (spin up, possible) So, (3,0,0, +4/2) is a possible quantum non c) (2,2,1, +42) n=2 (possible 1=2 (Not possible because, for given value of n I can have a values of ranging from o to n-1) So, (2, 2, 1, 14) not a possible decantan imber. d) ( 4,3,- 2,442) n = 4 (possible) 1=3 (possible) MEL (possible)

S=+4₂ (spin up) So, (4, 3, 2, +4/) is a possible quantum no e) ( 3, 2, 1, 1) n = 3 (possible) 1=2 (possible) mal possible) s=1 ( not possible, because s can have at two volue, +1 for spin up a -4₂ for spin down) So, (3, 2, 1, 1) is a not possible Quantum no. phosphorous acid (H₂PO₂) POH OH I Atomic number of phosphorous = 15 HOT H electronic Ground But in state, so electronic configuration of phosphorous in state - 152, 252ap6 352 3p² phosphorous, P is in to oxidation p has 15-3 = 12 elections configuration of p in phosphorous

acid = 1s?, ?s?aps, as? b) iron (1) chlorate - PelclO3)₂ th Atomic no. of cd is L7 So, Ground state electronic configuration - 152, 252 ap6 35² eps But in iron (111) Chlorate d is in +5 oxidor -ation state. So, the elections available in cd in Fe (CO₂). are 17-5 = 12 So, electronic configuration of I in fecclO3)3 is - 152,252 2p8, 352 c) potycsium permanganate ( kmuda) Atomic Mo. of Mu = 25. Ground state electronic configuration of mua - 152 as? apo 353p6 ods" But in KMnO4 , Mn is in +7 oxidation state. So, elections present in Mn are 25-7 = 18 o electronic confisch Mn in KMnO4 - 15 25² 28635206 -