Question

Ball Diameter (mm)Time from photogate (s) 0.006 Instructions: A single photogate is programmed to start a timer when it is blocked, and stop the timer when it is unblocked A sphere with constant velocity passes through the photogate. Using the appropriate data in the table, determine the speed of the sphere as it passes through the photogate. Assume that the beam of the photogate is aligned such that the photogate will collect data based on the sphere's diameter. All work must be shown on the back of this page. Your work should include a diagram of when the timer begins and ends. Questions: • What is the speed of the sphere in m/s ? (3 points) • A projectile is launched perfectly horizontally with a constant velocity. How much time in seconds will it take the projectile to fall a distance of 3 meters? (3 points) • A projectile is launched perfectly horizontally from a table height of 1.0 meters. How many meters will the projectile travel in the horizontal direction before it hits the floor, if its initial velocity is 4 m/s? (4 points)

Answer 1

The pass whole sphere takes 0.006 sec to and its diameter is 22mman 22x1013 m. speed= d= 22x10 .= 3.67 m/s so - 0.006 - As projectile is launched horizontally so intial vertical speed is zero. so. s= ut + hat? S=3m, a = 9.81 mist 3= } *9.81 xt2 » t- 13X2 U 9.81 0.782 see - tione to travell Im. to set as very hot ( 93 abones cas above) U 9:31 = 0.451 sec. Again is horizontal relocity is amis. and it travells for 0.451 sec - it will be 4x0.451= 1.81 m hos 2oos tally 28