Question

Problem 15-08 (Algorithmic) Refer again to the gasoline sales time series data in the following table. Week Sales (1000s of ga. Using a weight of 1/2 for the most recent observation, 1/3 for the second most recent, and 1/6 for third most recent, compb. Compute the MSE for the weighted moving average in part a. Do you prefer this weighted moving average to the unweighted moI just need help with those marked with a red X, and the last question thank you!

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Answer: 15-08 (Algorithmic) Refer again to the gasoline sales time series data in the following table.

Solution:

a)

Week sales

weight moving

average forecast

Forecast

Error

(Error)2
1 19
2 24
3 19
4 25 20.67 4.33 18.75
5 19 22.83 -3.83 14.67
6 16 21.00 -5.00 25
7 21 18.50 2.50 6.25
8 17 19.00 -2.00 4
9 22 18.17 3.83 14.67
10 21 20.17 0.83 0.69
11 15 20.67 -5.67 32.15
12 24 18.17 5.83 33.99
150.17

b) MSE = Total of (Error)2 / no. of week consider forecast

MSE = 150.17/9

MSE = 16.69

c) As weighted average is better as unweighted average. Therefore, Yes, we can find a set of weights that would make a MSE smaller for weighted average then unweighted moving average when weights are equal.

As per requirement I correct only those parts which are wrong. So, if you like please appreciate.

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