Question

The amount of time that customers wait in line during peak hours at one bank is normally distributed with a mean of 12 minutes and a standard deviation of 3 minutes. The percentage of time that the waiting time is less than 16 minutes is equal to the area under the standard normal curve that lies to the of left, 1.33 Oright, 1.08 O left. -1.33 Oright, 1.33

Answer 1

μ=12, σ=3

We need to compute Pr(X≤16). The corresponding z-value needed to be computed:

$Z = \frac{X - \mu}{\sigma} = \frac{ 16 - 12}{ 3} = 1.3333$

The percentage of time that the waiting time is less than 16 minutes is equal to the area under the standard normal curve that lies to the left of 1.33.