Question

9. My dog Bella lays on the lawn and with one eye open, sees her nemesis the fox squirrel venture But Irom the woods. When the squirrel is just close enough, 10m, she springs forward with an initial velocity of 3m/s and accelerating at 1 m/s2. Meanwhile, the squirrel freezes for 1 sec then accelerates at 2.0 m/s2 toward the nearest tree, 8 m away. (that's 18 m from where Bella was napping). YR Unisa a) b) Where is Bella and at what speed is she running when the squirrel starts accelerating? Show the details of your work to determine if Bella will finally catch a squirrel? If so when and where? If not, how close was she when the squirrel got to the tree? (If you didn't get your quadratic to solve assume t = 3 seconds after squirrel starts accelerating) What would Bella's velocity be if she runs into the tree? (even if she picked up the squirrel on the way)? 2.0m d)

Answer 1

tom- squished Tree otom Bella u-3m/ a, imp? az=2ms (b) V=utat = 3+ (141) - 4 | 0 s- uit & auth - 3+1) ++ +1417] = 3.5m Bella is sunning at hnis and is 6.5 manay from squirrel distance covered by bella in ţ seconds 4at, + L +9,62 = 6.75 +20 + 4t, + & t = 6.5th o distance covered by squirrel x = ust z at = 0 +2 +24,2) 20 ti? Pet value in ea 6 - 4t + t = 6.5 + te 2 t - 46, +6.5=0 - t = 2.26 795 se : 26 = 2.26795) ² 5.14364

s is less than the distance betingen squinel and tree .. Bella will catch squirrel (C) Bella caught squirrel 80s. 1436 - 2.856 m befor the tree Total time taken by Bella to catch squerid + (2.26795) 3.26 795 sec (d) Bellas velocity or - v² – U2 = eas v²_ (3) = 2(1)(18) v=(6-708 mis

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