Question

Take that the 80 kN load may be applied at any point on the circumference of the 40 mm radius circle shown. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. r= 40 mm 160 mm 100 mm Determine the value of for which the stress at Dreaches its largest value. The value of ois

Answer 1

1 2 ЧОМ p=20kn 160mm TOOL Mac 197r sine Tcost - Mz load p shifting hence moment ate develope at Mae center and of circle moment Mz. More = prsino = 80x40 sino = 3200 sino ang 80x40 cOSO = 3200 cosO NM Mz = prcoso =

Stress at point D is due to Axial load & load P moment Mre and moment M2 all are compressive nature. stress due to load 160x100 be 160x100 6 = 5 MPa 15 stress due to moment Mac San Ise Mae yaa 3200 sino x ( I ) - (-1)3(116) 12 sino MP of a o = ROOM stress due to mement Myz Iz 3200 coso I (0.16 3 x (0.1) 1² < 160 Iz~ 160 mm 7.5coso MPa

Total value of stress at point o is oo stoto = 5+ 12 sino & 7.5 coso (compressive) for maximum value doo - Cot 12 cose - 7.5 sino =0 12 coso = 70s sino tano = 12 705 ) O = tan" ( 12 o = stoggyo (6) max = s t 12 sin(57.994) +7.5 cos (57.994) (6) max = 19.1509 MPa (compressive)