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TUIE IIIJ UITLIULIUILT TULIT lile UMMC Duna Jurvey A survey conducted in July 2015 asked a random sample of American adults w

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Answer #1

p = 50/411 =0.1217

std.error = 0.016

z value at 90% = 1.64
Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, Zc = Z(α/2) = 1.64

CI = p +/- z *SE
= 0.1217 +/- 1.64 * 0.016
= (0.095 ,0.148)

The 90% CI is 0.095 to 0.148


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