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T2 X + v https://newconnect.mheducation.com/flow/connect.html pter 2 Help Save & Exit Submit Given the following observed phe

Given the following observed phenotypic ratios, calculate the expected phenotypic ratios and chi square values. Then evaluate the chi square value using a chi square table to accept or reject the null hypothesis at a P value of 0.05. Place the appropriate boxes in correct position in the table 

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T2 X + v https://newconnect.mheducation.com/flow/connect.html pter 2 Help Save & Exit Submit Given the following observed phe

Problem 1

Null hypothesis: The observed values are not deviating from the 9:3:3:1 ratio.

Observed values (O)

250

106

104

40

500

Exptected Ratio (ER)

9

3

3

1

16

Exprected Values (E)

281.25

93.75

93.75

31.25

Deviation (O-E)

-31.25

12.25

10.25

8.75

D^2

976.5625

150.0625

105.0625

76.5625

D^2/E

3.472222

1.600667

1.120667

2.45

8.643556

X^2

8.643556

Degrees of freedom

4-1=3

Inference: The calculated chisquar value i.e. 8.6 is greater than the table value i.e.7.82 at 3 DF and 0.05 probability, hence the null hypothesis is rejected.

Problem 2

Null hypothesis: The observed values are not deviating from the 1:1:1:1 ratio.

Observed values (O)

130

122

140

108

500

Exptected Ratio (ER)

1

1

1

1

4

Exprected Values (E)

125

125

125

125

Deviation (O-E)

5

-3

15

-17

D^2

25

9

225

289

D^2/E

0.2

0.072

1.8

2.312

4.384

X^2

4.384

Degrees of freedom

4-1=3

`

Inference: The calculated chisquar value i.e. 4.38 is less than the table value i.e.7.82 at 3 DF and 0.05 probability, hence the null hypothesis is accepted.

Problem 3

Null hypothesis: The observed values are not deviating from the 3:1 ratio.

Observed values (O)

350

150

500

Exptected Ratio (ER)

3

1

4

Exprected Values (E)

375

125

Deviation (O-E)

-25

25

D^2

625

625

D^2/E

1.666667

5

6.666667

X^2

6.67

Degrees of freedom

-

1

Inference: The calculated chisquar value i.e. 6.67 is greater than the table value i.e. 6.67 at 1 DF and 0.05 probability, hence the null hypothesis is rejected.

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