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7B.4 Flow between two tanks. Case 1: A fluid flows between two tanks A and B because Pa > PB. The tanks are at the same elevation and there is no pump in the line. The connecting line has a cross-sectional area S, and the mass rate of flow is w for a pressure drop of (PA -Ps(see Fig. 7B.4). Case I1: It is desired to replace the connecting line by two lines, each with cross section SSWhat pressure difference (PA P is needed to give the same total mass flow rate as in Case 1? Assume turbulent flow and use the Blasius formula (Eq. 6.2-12) for the friction factor. Neglect entrance and exit losses. Answer (PA-PPA-Pa)-2 Circular tube of cross section S Circular tubes of cross section S11 Mass flow rate w Sum of mass flow rates is w Fig. 7B.4 Flow between two tanks.
The answer is there but the method was confusing
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