Compute the capacitance of a parallel-plate capacitor with plates 5 cm by 4 cm, separation of 2 mm, and a mica dielectric
48.7 PF 68.2 pF 119.8 pF 169.5 pF
Compute the capacitance of a parallel-plate capacitor with plates 5 cm by 4 cm, separation of 2 mm, and a mica dielectric
An air-filled parallel-plate capacitor has a capacitance of 1.2 pF. The separation of the plates is doubled and wax is inserted between them. The new capacitance is 1.8 pF. Find the dielectric constant of the wax.
An air-filled parallel-plate capacitor has a capacitance of 1.4 pF. The separation of the plates is doubled and wax is inserted between them. The new capacitance is 2.1 pF. Find the dielectric constant of the wax.
A parallel plate capacitor has square plates of dimensions 5 times 5 cm and separation 2 mm. The space between the plates is filled with a material of dielectric constant K= 4. The charges on the plates are plusminus 5 times 10^-8 C. Find: the capacitance; the potential difference between the plates; the magnitude of the electric field between the plates; the electric energy density between the plates; and the total electric energy.
A parallel-plate capacitor has plates of area 3.55×10−4 m2 A) What plate separation is required if the capacitance is to be 1490 pF ? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059) B) What plate separation is required if the capacitance is to be 1490 pF ? Assume that the space between the plates is filled with paper. (Dielectric constant for paper is 3.7)
A parallel-plate capacitor has circular plates of 8.40 cm radius and 1.50 mm separation. (a) Calculate the capacitance. ???pF (b) What charge will appear on the plates if a potential difference of 118 V is applied? ???C
A parallel-plate capacitor has capacitance C0 = 7.00 pF when there is air between the plates. The separation between the plates is 1.10 mm. a. What is the maximum magnitude of charge Q that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 x 104 V/m? b. A dielectric with K = 2.60 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now...
A parallel-plate capacitor has a plate separation of 1.40 mm. If the material between the plates is air, what plate area A is required to provide a capacitance of 1.10 pF? ITn
A parallel-plate capacitor has a plate separation of 2.90 mm. If the material between the plates is air, what plate area A is required to provide a capacitance of 1.20 pF? m2
A parallel-plate capacitor has a plate separation of 2.30 mm. If the material between the plates is air, what plate area A is required to provide a capacitance of 1.50 pF? A : m2
dielectric constant of the paper is 3.5 The plates of a parallel plate capacitor are 4 cm wide and 6 cm long. The plates are separated by a 1.8-mm-thick layer of paper (a) Calculate the capacitance of the device (in pF) using the dielectric constant of paper from this table. 0.0836 X pF (b) Any dielectric material other than a vacuum has a maximum electric field that can be generated in the dielectric material before it physically or chemically breaks...