Question

please answer all parts fully, and please pay attention to wording and the wording of where the points are at. please show all work clearly and legibly. please show all equations and equation formulas, thank you very much for your help.

Tube of C86 bronze subjected to below loading. 3 mm mm 5 mm 25 N·m DO 4 1.5 m (a) 60 Nm G=38G Pa Determine: (a) Shear flow (a), (b) Shear stress (1) at point A (c) Shear stress (1) at point B (d) Angle of twist of C with respect to E.

Answer 1

Gaathi) Date GON SM OSN - 25 Noy beat = 40 mm dent = 60 mm bint = 40-10 = 30mm dint 60-6=54mme J 40w Ik = 40x60 - 30x5¢ =326340mm? 12 Gox 40° 54x30 = 198 soo mut 12 12 = 524840 mount Ip = In + ty 4 35 we know I h = 7 = Go or T Torque centre. CIAO T: shear stress A and B are on D E part 1 o:dist from IT: 35 Nm 16 For TA, T = 35Nm, Ip = 524840 mm and VA = 20 mm, TA = 35x70 x 20 394840 = 1.33 N/mm² Peçe no. A Page No.

Caathi) Date II ity for TB T= 35 Nm, Ip = 524840 mmit - VB = 30mm Té's 35% 10% x 30 524840 TB =. 2 N/mm² Dep 3 OD+ Opf G: Shear modulus - G = 43.66X10 N/mm TiLi & Ti L27 LIr 63 E 60X0.5 X 106 + 60* 35X1,5X106 18X43.66X924840 43.16 *10²x 52 4840 OCE = 3.64 103 rad. Oc-9€ = 3.68 10 rad. Oc = 3.6x10 rad.

Gaathi) Date of (a) shear flow - q = Tot In De portion - qA = TA. TA = 1.33*5 = 6.65 mm qB = TB XdB = 2x3 =6 N/mm. mm