Question 2.2 [2] Determine: a) the voltage VC across the 2μF capacitor, and b) the energy...

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Answer 1

Answer #1

Under steady state, inductor behaves like short circuit and capacitor behaves like open circuit. The circuit is redrawn as follows:

10.2. 수レ 6 mA 309 The ciut in dleaun by xe 2uf by y cweak durou on euro 60+30 312

Rest it becomes a simple resistive network. Hope you understood. A thumbs up is highly appreciated.

Answer 2

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