Question

Show calculations for how to prepare 500. mL of a 0.305 M HCl solution from concentrated HCl (conc. HCl= 12.3 M).

Answer 1

Using,

M1V1 = M2V2

Where M1, M2 = concentrated of initial and final solution

V1, V2 = initial and final volumes

Putting the respective values, we get

12.3 M x V1 = 0.305 M x 500 mL

V1 = 0.305 M x 500 mL / 12.3M

V1 = 12.39 mL

So, 12.39 volume of concentrated HCl must be diluted with (500 - 12.39) mL = 487.61 mL water to get the solution of desired concentration.