Question

(Revision 9) (6 points) 5. A cereal company makes three kinds of cereal with wheat, com, and oats. The proportions and profit of each cereal are shown in the table below. Set up the simplex tableau for this problem (do not solve the problem). W-O W-C-O W-C Wheat Corn Oats Profit/Kg 0.750 0.25 $0.30 0.50 0.25 0.25 $0.35 0.20 0.500 $0.25 The company has 300 kg of wheat, 240 kg of corn, and 400 Kg of oats. How many kilograms of each cereal should it produce to maximize profit? (10 points) 6. Follow the steps in the diagram "Simplex Method Summarized” in Section 6-2 in the textbook to maximize z = 2x, + 3x2 + 2xy, subject to the system 2x; + xy + 2x, S 13 *; + x2 – 3x, 58 *; 20, x, 20, x, 20

Answer 1

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Question No. 5

Hello friend !!! HAPPY TO ANSWER YOU. Given, . Max z = 0,30x + 0.352 + 0,25 23 subject to a 6 75 x + 0,50x2 +0.2003 <300 0.25% t 0.50x2 5240 0.2504 + 0.2502 < 400 2 U2, 3 > 0 → Table is given by, 24 22 23 -1 10.75 0.50 0.20 300 1 = - to 0 10.25 0.50 240 = -ta 0.25 0.250 400 - - tz 10.300.350.25 To 1 - f

Question No. 6

IA Q.6 Max Z = 271 +372 +223 sot. 22, + 22 +223 = 13 x + 22 - 32 = 8 - 2470 2270 x 320 Solution : Table is given by, 24 22 23 -1 * 2 1 1 2 1 13 sati TA B (8) i i -38 = -t2 col 1 2 3 2 o = € By wing simpley method for MBF. Current table is in MBF ( maximum basic feasible). - [0] ② 6 # All bi zo ; i=1,2 Here all c; to choose c = 2 © All ar $0 min & bi /aij so } = mins - The pivot on an=2 comesponding Desive table , | Rii s to p= 2. =-ta |--1/2 1*-8 3 T-14 10-265 Again following - current the table simplex is method for MBF. in MBF. © All bi 7,0 i=1,2 ② Not all gco @ choose C2=4 6 Not all ai so 6 min 5 13/2, 32 = 1. / - pivot on 922 =1 - to p=1 j = 1,2 3 conneaponding - We get table to tz 3/4 -12 15 15 - - I -8 31 = -a | | -4 / 32 -38 st Apply simplex algorithm for MBE Current tablets in MBF 0 All bi >0 - Not all ci so Choose t=1 7 Not all cui so 0 min { / 2 = 2 pirst on 9 = 36 We got table ① Similarly, on the previous way by ºusing simplex algorithm for MBA, 9,3 = 20 pinot pirst on a 9,3 = We get table , R, E, 4, -1 1/5 1-%013/20 15-23 3.778 | 3.667-3/40/28.33 = -22 |- 34.22 -4 -57/90-383.33|_ = £ is in MBF. table ③ bi 70 Cument ALL and all We get ci so optimal solution ☆ x = t;=t, .=0 23 3 3 28.33 = 383;33 and