Answer: -
11) Given demand = 800 videotapes per day
Working time = 8 hours in minutes = 8*60 = 480 minutes
a) Minimum cycle time is nothing but the longest task time = 0.6 minutes
Maximum cycle time is nothing but total of task time = 2.3 minutes
b) Cycle time = Operating time / Output per day
= 480 minutes / 800 videotapes per day = 0.6 minutes
c) Minimum number of stations required = total task time / cycle time
= 2.3 minutes/0.6 minutes = 3.83 ~ 4 stations
12) Given cycle time = 5.1 minutes
For station 1 idle time = cycle time - station time = 5.1 - 4.2 = 0.9 minutes
For station 2 = 5.1 - 4.7 = 0.4 minutes
For station 3 = 5.1 - 4.4 = 0.7 minutes
For station 4 = 5.1 - 4.8 = 0.3 minutes
Sum of all idle times = 0.9 + 0.4 + 0.7 + 0.3 = 2.3 minutes
Percent idle time = total idle time / (n*cycle time)
= 2.3 minutes/(4*5.1 minutes) = 2.3 / 20.4 = 11.27%
13) True
14) Option"D" --- Remain the same
15) Option"A" --- The EOQ
11. Management t wants to design an assembly line that will turn out 800 videotapes per...
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