The weight distribution of parcels sent in a certain manner is normal with mean of 12...
The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The parcel service wishes to establish a weight value c beyond which there will be a surcharge. What value of c is such that 99% of all parcels are under the surcharge weight?
Homework Answers
Given that,
mean = 
= 12
standard deviation = 
= 3
Using standard normal table,
P(Z < z) = 99%
= P(Z < z) = 0.99
= P(Z < 2.33) = 0.99
z =2.33 Using standard normal z table,
Using z-score formula
x= z *
+
x= 2.33 *3+12
x= 18.99
value of c =18.99
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