Draw and clearly label a diagram of the normal distribution
An airline knows that the mean weight of all pieces of passengers’ luggage is 49.7 lb with a standard deviation of 8.2 lb. What is the probability that the weight of 67 bags in a cargo hold is more than the plane’s total weight capacity of 3,600 lb?
Solution :
Given ,
mean = = 49.7*n=49.7*67=3329.9
standard deviation = = 8.2*n=549.4
P(x >3600 ) = 1 - P(x<3600 )
= 1 - P[(x -) / < (3600-3329.9) /549.4 ]
= 1 - P(z <0.49 )
Using z table
= 1 - 0.6879
= 0.3121
probability= 0.3121
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