Question
question 5
5. (a) A sample of 12 of bags of Calbie Chips were weighed (to the nearest gram), and listed here as follows. [9 marks] 219,
0 0
Add a comment Improve this question Transcribed image text
Answer #1

a ) using excel>addin>phstat>confidence interval

we have

Confidence Interval Estimate for the Mean
Data
Sample Standard Deviation 5.033222957
Sample Mean 222.6666667
Sample Size 12
Confidence Level 95%
Intermediate Calculations
Standard Error of the Mean 1.452966315
Degrees of Freedom 11
t Value 2.2010
Interval Half Width 3.1980
Confidence Interval
Interval Lower Limit 219.47
Interval Upper Limit 225.86

95% confidence interval for the mean mass of bags of Calbie Chips is (219.47,225.86)

2 ) using excel>addin>phstat>two sample test

we have

Pooled-Variance t Test for the Difference Between Two Means
(assumes equal population variances)
Data Confidence Interval Estimate
Hypothesized Difference 0 for the Difference Between Two Means
Level of Significance 0.05
Population 1 Sample Data
Sample Size 12 Confidence Level 90%
Sample Mean 78.8
Sample Standard Deviation 8.5 Intermediate Calculations
Population 2 Sample Degrees of Freedom 19
Sample Size 9 t Value 1.7291
Sample Mean 86 Interval Half Width 46.2762
Sample Standard Deviation 93
Confidence Interval
Intermediate Calculations Interval Lower Limit -53.4762
Population 1 Sample Degrees of Freedom 11 Interval Upper Limit 39.0762
Population 2 Sample Degrees of Freedom 8
Total Degrees of Freedom 19
Pooled Variance 3683.5132
Standard Error 26.7626
Difference in Sample Means -7.2000
t Test Statistic -0.2690
Two-Tail Test
Lower Critical Value -2.0930
Upper Critical Value 2.0930
p-Value 0.7908

the 90% confidence interval for the difference in midterm test scores of the two sections is (-53.4762,39.0762)

since confidence interval contains 0 so we do not have sufficient evidence to conclude that that one section of students are ”smarter” than the other section.

Ans 3 ) using excel>addin>phstat>two sample test >z test for difference of proportion

we have

Z Test for Differences in Two Proportions
Data Confidence Interval Estimate
Hypothesized Difference 0 of the Difference Between Two Proportions
Level of Significance 0.05
US Data
Number of Items of Interest 33288 Confidence Level 92%
Sample Size 671493
UK Intermediate Calculations
Number of Items of Interest 14606 Z Value -1.7507
Sample Size 109754 Std. Error of the Diff. between two Proportions 0.0011
Interval Half Width 0.0019
Intermediate Calculations
Group 1 Proportion 0.049573115 Confidence Interval
Group 2 Proportion 0.133079432 Interval Lower Limit -0.0854
Difference in Two Proportions -0.08350632 Interval Upper Limit -0.0817
Average Proportion 0.0613
Z Test Statistic -106.9171
Two-Tail Test
Lower Critical Value -1.9600
Upper Critical Value 1.9600
p-Value 0.0000
Reject the null hypothesis

we will conclude that the difference in the mortality rates in  US is lower than UK becasue confidence interval contain only negative numbers the 92% confidence interval in the true difference in the mortality rates between the two countries is (-0.0854 ,-0.0817)

Add a comment
Know the answer?
Add Answer to:
question 5 5. (a) A sample of 12 of bags of Calbie Chips were weighed (to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • COVID 19 statistics as at July 28, 2020: there were 4 426 281 confirmed cases and...

    COVID 19 statistics as at July 28, 2020: there were 4 426 281 confirmed cases and 151 374 deaths in the United States. There were 30 961 confirmed cases, and 998 deaths in Japan. You need to test if the COVID 19 mortality rate (proportion) in the United States is significantly higher than the mortality rate (proportion) in Japan. Write down the null and alternative hypotheses to be tested. Clearly define the terms used.    What is the type of...

  • a) A random sample of 15 employees of airtel call Centre was taken and each employee...

    a) A random sample of 15 employees of airtel call Centre was taken and each employee took a competency test. The mean of the scores achieved by these employees was 56.3 with a standard deviation of 7.1. Results of this test have been found to be normally distributed in the past. Construct a 95% confidence interval for the mean test score of all the employees of the call Centre. [6 marks] b) Find a 95% confidence interval estimating the mean...

  • Students investigating the packaging of potato chips purchased 0 bags of chips marked with a net...

    Students investigating the packaging of potato chips purchased 0 bags of chips marked with a net weight of 20.5 grame. They carefully weighed the contents of each bag, recording the following weights in gramas: 20.2.2.1, 29.1, 288, 28.8. Click the boon to wow the table Do the data willy the sumptions for interence? Is the randomization condition satufet? OA Yes, there is definitely evidence to believe that the bags of chips were sampled at random O No, the bags were...

  • QUESTIUN '13 Psychology Final Question 1 A professor teaches two sections of a Psychology class. The...

    QUESTIUN '13 Psychology Final Question 1 A professor teaches two sections of a Psychology class. The placement of the enrolled students in the two sections is done randomly. In Section 1, students are required to participate in weekly study groups. In Section 2, there is no such requirement. The data file FINAL.MWX (for Minitab 19) or FINAL.MTW (for Minitab 18) contains the final exam scores of students in these two sections. Let p1 and 2 denote the average score in...

  • COVID 19 statistics as at July 28, 2020: there were 4 426 281 confirmed cases and...

    COVID 19 statistics as at July 28, 2020: there were 4 426 281 confirmed cases and 151 374 deaths in the United States. The worldwide mortality rate is 3.95%. You need to test if the mortality rate (proportion) in the Unites States is significantly lesser than the worldwide mortality rate. Write down the null and alternative hypotheses to be tested. Clearly define the terms used. What is the type of statistical test procedure that should be used to test the...

  • s. QUESTION 2 Use minitab Suppose a sample of 20 students were given a diagnostic test...

    s. QUESTION 2 Use minitab Suppose a sample of 20 students were given a diagnostic test before studying a particular module and then again after completing the module. We want to find out if, in general, our teaching leads to improvements in students' knowledge/skills (i.e. test scores). We can use the results from our sample of students to draw conclusions about the impact of this module in general. 92.MPJ 1) check assumption (fort show your correct 3) find the t-value...

  • Question 17 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated...

    Question 17 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of a shift 15 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 15 bags yielded the following data. mean - 19.45 s - .64 n = 15. Based on a BOE-.354 for a 95% Confidence Interval for the...

  • Consider each of the scenarios below. For each statement, decide which statistical procedure is most appropriate....

    Consider each of the scenarios below. For each statement, decide which statistical procedure is most appropriate. One-sample hypothesis test for a single proportionOne-sample confidence interval for a single proportionTwo-sample hypothesis test for the difference in proportionsTwo-sample confidence interval for the difference in proportions Chi-square test for multiple categories of a single variable Chi-square test of independence of 2 categorical variables One-sample hypothesis test for a single mean One-sample confidence interval for a single mean Two-sample hypothesis test for the difference...

  • (5 points) Consider each of the scenarios below. For each statement, decide which statistical procedure is...

    (5 points) Consider each of the scenarios below. For each statement, decide which statistical procedure is most appropriate. 1. Mr. Taylor's 4th grade class uses Skittles to learn about probability. They open several randomly selected bags of Skittles and sort and count the different colors and want to determine if Skittles are evenly distributed by color. 2. An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had...

  • Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated...

    Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT