Solution :
Given that,
= 44102
= 9696
n = 140
A ) At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
a) Margin of error = E = Z/2* (/n)
= 1.645 * (9696 / 140 ) = 1347.89
b)At 95% confidence interval estimate of the population mean is,
- E < < + E
44102 - 1347.89 < < 44102 + 1347.89
Answer :- 42754.11 < < 45449.89
(42754.11,45449.89)
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